Help me with the workings to these questions please!!!
Ans7. Marginal cost = d(total cost) / d(quantity)
Marginal cost with respect to good 2:
= 1/4(c(x^1/2)y^(-3/4)) + h ......eq(1)
C = 0.1 ; h =25 , x =15 ; y = 34
Substituting the given values in eq(1)
1/4(0.1(15^(1/2) × 34^(-3/4)) + 25
= 25.0069
Ans 8.) To find the local minima , we first find the first derivative of the given equation with respect to 'x'
f'(y) = 4a(x^3) + 3b(x^2)
Put f'(y) = 0
4a(x^3) + 3b(x^2)= 0
As , a = 17 , b = 17 , c = 320
x^2(4ax + 3b) = 0
Which gives ,
X^2 = 0 => x = 0
4ax + 3b = 0 => x = -3(17)/4(17)
=> x = -0.75
The 2 critical points are:
x = -0.75 ; x = 0
Put x = 0
f(0) = 17(0)^4 + 17(0)^3 + 320
f(0) = 320
Put x = -0.75
f(-0.75) = 17(-0.75)^4 + 17(-0.75)^3 +320
f(-0.75) = 307.44
As we can see that the value of the given equation is low at x = -0.75.
So local minima = - 0.7500
Help me with the workings to these questions please!!! Question 7 Not answered Marked out of...
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