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7. Let C represent the event that a person has cancer. Let D represent the event that a person is diagnosed with cancer. In a certain region of the country it is known from past experience that the probability of selecting an adult over 40 years of age with cancer is 0.08. The probability of a doctor correctly diagnosing a person with cancer as having the disease is P(D C) 0.84, and the probability of incorrectly diagnosing a person without cancer as having the disease is P(DC)0.04. What is the probability that a person diagnosed as having cancer actually has the disease, i.e. find P(C | D)? Round all values to 4 decimals, if needed

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Answer #1

This problem is based on the principle of conditional probability and application of baye's theorem:-

SoJichon- c.- Pe γ son has conce- P(C)8 y Now P(D) P (D) ニ 10-24) x (0.08) 0 079 0-10千 0.0672十0.0368

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