concentration Fe2+ = 0.2619 M
Explanation
concentration MnO4- = 0.1138 M
volume MnO4- = 18.41 mL
moles MnO4- = (concentration MnO4-) * (volume MnO4-)
moles MnO4- = (0.1138 M) * (18.41 mL)
moles MnO4- = 2.095 mmol
moles Fe2+ = (moles MnO4-) * (5 moles Fe2+ / 1 mole MnO4-)
moles Fe2+ = (2.095 mmol) * (5 / 1)
moles Fe2+ = (2.095 mmol) * (5)
moles Fe2+ = 10.475 mmol
concentration Fe2+ = (moles Fe2+) / (volume Fe2+)
concentration Fe2+ = (10.475 mmol) / (40.00 mL)
concentration Fe2+ = 0.2619 M
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