Question

4 Using the following thermochemical equation, determine the amount of heat produced per kg of CO2 formed during the combustion of benzene (C6H6). 2 C6H6()+15 02(g)12 CO2(g ) + 6 H20(g) A) 1.43 x 105 kl/kg CO2 B) 2.30x 104 kl/kg CO2 AH"xn-6278 kJ C) 4.34 x 104 kl/kg CO2 D) 1.19x 104 kl/kg CO2 E) 8.40x 105 kl/kg CO2 48) Using the following equation for the combustion of octane, calculate the amount of moles of carbon dioxide formed from 100.0 g of octane. The molar mass of octane is 114.33 g/mole. The molar mass of carbon dioxide is 44,0095 g/mole. 2 C8H18+ 25 O2 16 CO2 + 18 H20 AH rxn-11018 kJ A) 18.18 moles B) 6.997 moles C) 14.00 moles D) 8.000 moles E) 10.93 moles 49) Calculate the mass percent composition of lithium in Li3PO4. A) 26.75 % B) 17.98 % C) 30.72 % D) 55.27 % E) 20.82 % 50) According to the following thermochemical equation, what mass of HF (in g) must react in order to produce 345 kJ of energy? Assume excess SiO2. SiO2(s)+ 4 HF(g) SiF4lg)+ 2 H2O(I) AH"rxn = -184 k A) 42.7 g B) 37.5 g C) 150. g D) 107 g E) 173 g 51) What is the chemical name for P214? A) phosphorous (IV) iodine B) diphosphorous tetraiodine C) phosphorous tetraiodine D) phosphorous (I) iodine E) diphosphorous iodine
can you do all of them please

Answer 1

kindly post different questions separately. please rate

117 2 CG H6 (1) + 1502 (9) 1200, 19) + 6H₂O(g) Stixn=-6278 KI - To produce 12 mola of CO2 amount of heat produce = 6278 KJ molar man of CO2 = 44 g/mol 1000g = 1kg To produce 12x44g of co₂, amount of heat produce 6278 KJ To produce 1000 g ie 1kg af iCo, amount of heat produce = 6278 KT x 1000g & 1.19 8104 kJ 12 x 443 amount of heat produced per kg of co, form is 1.19 X 104 KT I Koco, Hence, option o) is conect