Using the following thermochemical equation, determine the amount of heat produced when forming one kg of CO2 during the combustion of benzene (C6H6).
2C6H6(l) + 15O2(g)→12CO2(g) + 6H2O(g)
ΔH°rxn =-6278kJ
Molar mass of CO2,
MM = 1*MM(C) + 2*MM(O)
= 1*12.01 + 2*16.0
= 44.01 g/mol
mass(CO2)= 1 Kg
= 1000.0 g
use:
number of mol of CO2,
n = mass of CO2/molar mass of CO2
=(1*10^3 g)/(44.01 g/mol)
= 22.72 mol
Since Δ H is negative, heat is released
when 12 mol of CO2 reacts, heat released = 6278.0 KJ
So,
for 22.72 mol of CO2, heat released = 22.72*6278.0/12 KJ
= 1.189*10^4 KJ
Answer: 1.19*10^4 KJ
Using the following thermochemical equation, determine theamount of heat produced when forming one kg of...
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can you do all of them please
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