Calculate ΔH∘f (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) ΔH∘ = -6534kJ ΔH∘f (CO2) = -393.5kJ/mol ΔH∘f (H2O) = - 285.8kJ/mol
Calculate ΔH∘f (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) ΔH∘ =...
Part A Calculate AH (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(1) + 1502 (g)+12C02(g) + 6H2O(1) AH° = -6534kJ AH (CO2) = -393.5kJ/mol AH (H2O) = - 285.8kJ/mol O ALQ 6 A 0 2 ? AH = kJ/mol Submit Request Answer
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g) --> 12CO2(g)+6H2O(l)+6542kJ If 8.000 g C6H6 is burned and the heat produced from the burning is added to 5692 g of water at 21 C, what is the final temperature of the water? final temperature: _________________ C
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 6.200 g C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘ C, what is the final temperature of the water?
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 5.500 g C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘ C, what is the final temperature of the water?
Consider this reaction: 2C6H6 + 15O2 --> 12CO2 + 6H2O If you start with 1.5 moles of C6H6 and 10 moles of O2, then: how many moles of CO2 can be formed? how many moles of H2O can be formed?
the following equations is the balanced combustion reactions for c6h6 2C6H6(l)+15O2---->12CO2(G)+6H20(l)+6542 k j if 7.700 g of C6H6is burned and the heat produced from the burning is added to 5691 g of water at 21 c what is the final temperature of the water?
Using the following thermochemical equation, determine the amount of heat produced when forming one kg of CO2 during the combustion of benzene (C6H6).2C6H6(l) + 15O2(g)→12CO2(g) + 6H2O(g)ΔH°rxn =-6278kJ
What volume of benzene (C6H6, d=0.88g/ml, molar mass =78.11g/mol) is required to produce 1.5•10*3kj of heat according to the following rxn?: 2C6H6(l) + 15O2(g)—-> 12CO2(g) + 6H2O(g) delta H rxn= -6278kj
The standard enthalpy change for the reaction of SO3(g) with H2O(l) to yield H2SO4(aq) is ΔH∘ = -227.8 kJ .? Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO4(aq) (in kilojoules per mole). [For H2O(l),ΔH∘f = -285.8kJ/mol]. Express your answer using four significant figures.
Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l)+8O2(g)→5CO2(g)+6H2O(g),ΔHC(s)+O2(g)→CO2(g),ΔH2H2(g)+O2(g)→2H2O(g),ΔH===−3244.8kJ−393.5kJ−483.5kJ Express your answer to four significant figures in kilojoules.