Heat of reaction,
where, np and nr stands for the moles of products and moles of reactants respectively.
Thus,
(moles of CO2) x (CO2) + (moles of H2O) x (H2O) - (moles of C6H6) x (C6H6) - (moles of O2) x (O2)
or, - 6534 kJ = 12 mol x (- 393.5 kJ/mol) + 6 mol x (- 285.8 kJ/mol) - (moles of C6H6) x (C6H6) - 0 [(O2) = 0 as oxygen is in its standard elemental state)
or, - 6534 kJ = - 4722 kJ - 1714.8 kJ - 2 mol x (C6H6)
or, (C6H6) = 48.6 kJ/mol
Hence, of benzene = 48.6 kJ/mol
Part A Calculate AH (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(1)...
Calculate ΔH∘f (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) ΔH∘ = -6534kJ ΔH∘f (CO2) = -393.5kJ/mol ΔH∘f (H2O) = - 285.8kJ/mol
When one mole of benzene, CoHo is burned in O2 to produce CO2 and H2O, AH = -3300 kJ. What is AH for the following reaction: 12 CO2 + 6H2O → 2 C6H6 + 15 O2 a. -6600 kJ b. 6600 kJ C. 3300 kJ d. 1100 kJ e. None of the above
The standard enthalpy change for the reaction of SO3 (g) with H2O(l) to yield H2SO4 (aq) is AH° = -227.8 kJ. Part A Use the following information S(s) + O2(g) +SO2(g), AH° = -296.8kJ SO2(g) + 1 O2(g) +S03 (g), AH° = -98.9kJ to calculate AH; for H2SO4(aq) (in kilojoules per mole). [For H2O(l), AH = -285.8kJ/mol]. Express your answer using four significant figures. O AXO A o ai ? AH; = Submit Request Answer Provide Feedback
MTBE (C5H120) is a gasoline additive. Write a balanced equation and calculate AH in kilojoules (15 points) CsH120(1) + O2(g) + CO2(g) + H2O(1) AH°F (CsH120) = -313.6 kJ/mol AHºf (CO2) = -393.5 kJ/mol AHºf (H2O) = -285.8 kJ/mol
Calculate the molar enthalpy of combustion of cinnamaldehyde (AH comb) (in kilojoules per mole of cinnamaldehyde). kJ/mol 45
Calculate the fuel value,expressed in units of kJ/g, for gaseous benzene (C6H6) I tried -40.56 it is not correct Calculate the fuel value,expressed in units of kJ/g, for ethylene gas (C2H4) I tried -47.16 it is not correct < . Chapter 19: Organic Chemistry 15 Question (s points) Compound C&H.(8) A°H, (kJ/mol) 82.9 52.3 -393.5 -285.8 -241.8 co2(g) 20 (0 H20(g ︾ 2nd attempt Part 1 (2.5 points) Calculate the fuel value, expressed in units of kilojoules per gram, kJ/g,...
Part G Calculate AH for the following reaction: CH3OH(1) +O2(g) + HCOH(1) +H2O(1) Express the enthalpy in kilojoules to one decimal place. AC O O ? AH = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part 1 Calculate AS for the following reaction: CHOH(1) +O2(g) + HCO-H1) +H2O(1) Express the entropy in joules per kelvin to one decimal place. IVO AED ROO? J/K AS = Submit Request Answer Part 1 From the values of AH°...
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
Write a balanced equation for the combustion of benzene, C6H6(l) . If the standard heat of combustion of benzene is –3271 kJ/mol. Calculate its standard heat of formation, H°f , given the following data: ( 4 pts) H°f [CO2(g)] = –394 kJ; H°f [H2O(l)] = –286 kJ