MTBE (C5H120) is a gasoline additive. Write a balanced equation and calculate AH in kilojoules (15...
5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2 Fe2O3 (s) AH1 of FeO (s) = -272.0 kJ/mol AHºf of Fe2O3 (s) = -825.5 kJ/mol 3. Given 3 C (s) + 4 H2(g) → C3H8 (9) AH = -103.85 kJ/mol C(s) + O2(g) + CO2(g) AH = -393.5 kJ/mol H2 (g) + 12 O2(g) → H2O (1) AH = -285.8 kJ/mol find AH for C3H8 (g) + 5 O2(g) → 3 CO2 (g)...
The combustion of lauric acid is given by the following thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) + 12 CO2(g) Hcomb is −7377 kJ mol−1 Using the heats of formation for CO2(g) and H2O(l) calculate the heat of formation (△fH) of lauric acid. △fH△ CO2(g) = −393.5 kJ mol−1 fH H2O(l)= −285.8 kJ mol−1 19. The combustion of lauric acid is given by the following thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) + 12 CO2(g) AH...
Given the following balanced equation for the combustion reaction of an unknown fuel: 4 Fuel (1) + 902(9) -> 8C02(g) + 10H 20(1) + AHørxn = -3857 kJ/mol 2N2(g) Given that AH°f{CO2(g)) = -393.5 kJ/mol and AH°f[H2001)) = -285.8 kJ/mol, calculate the enthalpy of formation of this fuel. Write answer to four significant figures. Numeric Response
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
UJUH POHL Given the following information: Using the data given below at 25°C, calculate the change in enthalpy (DH) for the following reaction: 2PC13(g) + O2(g) ® 2POC13(g) Calculate the AH°rxn for the combustion of ethanol using the given AH°F. AHºf, ethanol (1) = -277.6 kJ/mol AHºf, water (1) = -285.8 kJ/mol AHºf, carbon dioxide (g) = -393.5 kJ/mol
Sucrose, C12H22011, is table sugar, and it has a (enthalpy of reaction) AH. of –5639.7 kJ/mol. Determine the AH; of sucrose given AH+ (H2O(1)) = -285.8 kJ/mol, and AH+ (CO2(g)) = -393.5 kJ/mol. [3] C12H22O4(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(1)
loab beboo 2CO2 + H2O. 7. Calculate AH for C2H2 +5/202 Given C(s) +O2(g) CO2(g) AH = -393.5 kJ H2+½ O2 H2O AH= -285.8 kJ 2C+H2 C2H2 AH = 226.8 kJ 008700000 08.0 Lon Qoe cOeEo.O60
Isooctane C3H18 is a major component of gasoline. Determine the change in enthalpy for the combustion of 2.000 mol of isooctane from the following data: H2(g) + (1/2)02(g) + H2O(g) AH° = –241.8 kJ C(s) + O2(g) + CO2(g) AH° = -393.5 kJ 8C (s) + 9H2(g) → CgH 18 (1) AH° = -224.13 kJ Isooctane CgH 18 is a major component of gasoline. Determine the change in enthalpy for the combustion of 2.000 mol of isooctane from the following...
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol