Sucrose, C12H22011, is table sugar, and it has a (enthalpy of reaction) AH. of –5639.7 kJ/mol....
Sucrose (table sugar, C12H22O11) can be oxidized to CO2 and H2O, and the enthalpy change for the reaction can be measured. C12H22O11(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(ℓ) ΔHrxn° = -5645 kJ/mol-rxn What is the enthalpy change when 7.00 g of sugar is burned under conditions of constant pressure? kJ
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
Table sugar (sucrose) is hydrolyzed to form glucose (a simple sugar) according to the following equation: C12H220 i 1 (s)-H2O(g)→2C6H 1206(s) Determine the enthalpy change for the hydrolysis reaction given the following information: C12H22011 (s) + 1202(g) → 12CO2(g) + i i H2O(g) AH-5640 kJ C,H,..(s) + 602(g)-→ 6CO2(g) + 6H20(g) 6 126 H2800 kJ rxn kj
[32] The enthalpy of reaction for [6] enthalpy of reaction for the combustion of C to CO, is-393.5 kJ/mol C, and the enthalpy for the combustion of CO to CO, is-283.0 kJ/mol CO: (i) C(s) + O2(g) + CO2(e) AH -393.5 kJ CO(g) + O2(g) + CO2(g) AH -283.0 kJ Using these data, calculate the enthalpy for the combustion of C to CO. (iii) C(s) + O2(g) - CO(g) AH-?
Given the following standard enthalpy of formations: AH [C,H,OH() --277.7 kJ/mol; AH(CH3CO,H() = -484.5 kJ/mol); AH® [H2O(1) --285.8 kJ/mol]; AH [O2(g) - 0 kJ/mol). Calculate the AHan for the reaction. C,H,OH(I)+,(g) → CH,CO,H(1) + H2O(l)
The following table lists some enthalpy of formation values for selected substances. Substance ΔfH∘ΔfH∘ (kJ mol−1)(kJ mol−1) CO2(g)CO2(g) −393.5−393.5 Ca(OH)2(s)Ca(OH)2(s) −986.1−986.1 H2O(l)H2O(l) −285.8−285.8 CaCO3(s)CaCO3(s) −1207−1207 H2O(g)H2O(g) −241.8−241.8 Part A: Determine the enthalpy for this reaction: Ca(OH)2(s)+CO2(g)→CaCO3(s)+H2O(l) C a ( O H ) 2 ( s ) + C O 2 ( g ) → C a C O 3 ( s ) + H 2 O ( l ) Express your answer in kJ mol−1 k J m o l...
7. The enthalpy of combustion of C to CO2 is –393.5 kJ/mol C, and the enthalpy of combustion of Co to CO2 is -283.0 kJ/mol CO: C(s) + O2(g) + CO2(g) AH = -393.5 kJ CO(g) + 102(9) CO2(g) AH = -283.0 kJ Using these data, calculate the enthalpy of combustion of C to CO: C(s) + O2(g) → CO(g) AH = ? Answer: -110.5 kJ
Use the Data table to calculate ∆H for the reaction below:Reactions: Change in Enthalpy (∆H)(1) C (s) + O2 (g) -> CO2(g) ∆H1 = -393.5 kJ/ mol(2) H2 (g) + 1/2 O2 (g) -> H2O (l) ∆H2 = -285.8 kJ/mol(3) 2C2H6 (g) + 7O2 (g) -> 4 CO2 (g) + 6 H2O (l) ∆H3 = -283.0 kJ/molCalculate the enthalpy change for the reaction:2 C (s) + 3 H2 (g) -> C2H6(g) ∆H = ______________kJ/mol
Hence, the reaction enthalpy for the overall reaction is-297 kJ + (-99 kJ) = -396 kJ. Part C Hess's Law of Constant Heat Summation button within the activity and use the example shown to calculate the reaction enthalpy, AH CH, (g)+202 (g)-CO2 (g ) + 2H,O(1) Use the series of reactions that follow: Click on the for the following reaction: 1. C(s)+2H2 (g)->CH, (g). AH= -74.8 kJ. C)+O2 g)-CO2(g), AH= -393.5 kJ. 3. 2H2 (g) +O2(g) -+2H,6(g), AH-484.0 kJ 4....