Given the following standard enthalpy of formations: AH [C,H,OH() --277.7 kJ/mol; AH(CH3CO,H() = -484.5 kJ/mol); AH...
4. Given the following standard enthalpy of formations: AH° C,H,OH() =-277.7 kJ/mol]; AHO [CH CO H) = 484.5 kJ/mol]; AH° [HO) = -285.8 kJ/mol]; AH° (O,(g) 0 kJ/mol] UnvIL Calculate the LDH for the reaction. CH.OHI)+0,(g)- CH,CO,H() H,O()
6. Given the following thermochemical reactions 2NO N,+O 2NO+O,2NO AH=-180 kJ AH=-112 kJ Calculate the enthalpy change of the reaction of nitrogen with oxygen to produce nitrogen dioxide. N,+20,2NO, AH r? Lo Given the following standard enthalpy of formations: AHor [C2H$OH(I) =-277.7 kJ/mol]; AHOr [CHCO2H) =-484.5 kJ/mol]; AHr [H2O) = -285.8 kJ/mol]; AHn[O2(g) = 0 kJ/mol]. Calculate the AHn for the reaction. C,H.OH()+O,(g) ->CH,CO,H() + H2O(1)
3. Mothballs are composed primarily of the hydrocarbon naphthalene (C,H). When 1.25 g naphthalene is burned in a bomb calorimeter, the temperature rises from 25.25 °C to 34.33 °C. (Heat capacity of calorimeter 5.11 kJ/°C). Calculate: a) The heat of reaction per gram of naphthalene b) The heat of reaction per mole of naphthalene Given the following standard enthalpy of formations: AH°, [C,H,OHO --277.7 kJ/mol]; AH [CHCOH) = 484.5 kJ/mol]; AH [HO) = -285.8 kJ/mol]; AH® [0,(g) - 0 kJ/mol].
ate the standard enthalpy change for the reaction Given standard enthalpy of formations △H; (SO(g))--395.2 kJ/mol Δ} l; (SO2(g))--296.9 kJ/mol al 201.0 kJ 403 J 254.6 kJ - 120.4 k.J - 196.6 kJ dl
Sucrose, C12H22011, is table sugar, and it has a (enthalpy of reaction) AH. of –5639.7 kJ/mol. Determine the AH; of sucrose given AH+ (H2O(1)) = -285.8 kJ/mol, and AH+ (CO2(g)) = -393.5 kJ/mol. [3] C12H22O4(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(1)
6. Given H2(g) + 22 O2(g) → H2O(1), AH° = -286 kJ/mol, Determine the standard enthalpy change for the reaction 2H2O(l) → 2H2(g) + O2(g) (2 pt)
3) Calculate the AH,º for the following reactions based on the standard heat of enthalpy of each compound. AH° (kJ/mol): HCl(g) → -92.3, NaCl(s) →-411.0, NaOH(s) →-426.7. H2O(g) +-241.8 SO2(g) → -296.8, H2S(g) → -20.0, O2(g) → 0.0, H2O(l) →-285.8 a) NaOH(s) + HCl(g) ----> NaCl(s) + H2O(g) b) 2 H2S(g) + 3 O2(g) ---> 2 H2O(l) + 2 SO2(g)
Calculate the standard enthalpy of formation of CS2() given that AH=-393.5 kJ/mol AHo = -296.4 kj/mol a. C(s) + O2(g) CO2lg) b. S(s) +O2(g). SO2(g) AH = -1073.6 kj/mol C. CS2(I)+302(g) Co2lg) + 2S02(B)
[32] The enthalpy of reaction for [6] enthalpy of reaction for the combustion of C to CO, is-393.5 kJ/mol C, and the enthalpy for the combustion of CO to CO, is-283.0 kJ/mol CO: (i) C(s) + O2(g) + CO2(e) AH -393.5 kJ CO(g) + O2(g) + CO2(g) AH -283.0 kJ Using these data, calculate the enthalpy for the combustion of C to CO. (iii) C(s) + O2(g) - CO(g) AH-?
The following table lists some enthalpy of formation values for selected substances. Substance ΔfH∘ΔfH∘ (kJ mol−1)(kJ mol−1) CO2(g)CO2(g) −393.5−393.5 Ca(OH)2(s)Ca(OH)2(s) −986.1−986.1 H2O(l)H2O(l) −285.8−285.8 CaCO3(s)CaCO3(s) −1207−1207 H2O(g)H2O(g) −241.8−241.8 Part A: Determine the enthalpy for this reaction: Ca(OH)2(s)+CO2(g)→CaCO3(s)+H2O(l) C a ( O H ) 2 ( s ) + C O 2 ( g ) → C a C O 3 ( s ) + H 2 O ( l ) Express your answer in kJ mol−1 k J m o l...