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5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2...
Using standard heats of formation calculate AH for 4 FeO (s) + O2 (g) 2 Fe...
Using standard heats of formation calculate AH for 4 FeO (s) + O2 (g) 2 Fe Os (s) AHr of FeO (s) - -272.0 kJ/mol 5 AH'T of Fe2O3 (s) = -825.5 kJ/mol
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) +...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) +...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) + 6 F2 (g) → 2 CF4(g) + 4 HF (9) can be written as the sum of: CH4 (9) ► 2 C(s) + 2 Ha(o) AH = -52.3 kJ/mol 2 C(s) + 4 Faq) → 2 CF4g) SH -1380 kJ/mol 2 Haq) + 2 Fala) > 4 HF HE.1074 kJimol CsHe(g) + 6 F2 (g) → 2 CF.(g) + 4 HF (g) AH =...
2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5...
2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5 H2(g) → C2H6 (g) + 2 H2O(g) Compound AH°F (kJ/mol) Compound AH°F (kJ/mol) 52.28 C₂H6 (8) -84.68 C2H4 (8) -393.5 CO2(g) -241.8 H2O(g) -285.9 CO(g) -110.5 H2O(1)
a Using the heats of formation below, calculate the heat of reaction for the following reaction:...
a Using the heats of formation below, calculate the heat of reaction for the following reaction: C2H2(g) + 5/202(2)→ 2C02() +H20() AH® (kJ/mol) C2H2(g) 226.7 O2(g) 0 CO2(g) -393.5 H20(-285.8 kJ Submit b Using the heats of formation below. calculate the heat of reaction for the following reaction: PC13(2) + Cl2(2)→ PC15(e) AH(kJ/mol) PC13(g) -306.4 Cl2(E) 0 PC1s() -398.9
4. If NaHe ()+ Oz (g) Na (g)+ 2 HO (0) Ha (g) +% O (g)...
4. If NaHe ()+ Oz (g) Na (g)+ 2 HO (0) Ha (g) +% O (g) H:O (1) Hz (g)+ O2 (g) H2O: () Find AH for N He ()+2 HzO2 (I) N: (g) +4 H2O () AH 622 2 k/mol AH-285 8 kJ/mol AH-187 8 kJ/mol 5. Using standard heats of formation, calculate AH for 4 FeO (s)+ O2 (g) 2 Fe:Os (s) -272.0 kJ/mol AH'r of FeO (s) AH'r of FeaOs (s) = -825.5 kJ/mol 6. Using standard...
1. Find the heat of combustion of liquid toluene (C6H5-CH3) Table of Heats of Formation Substance...
1. Find the heat of combustion of liquid toluene (C6H5-CH3) Table of Heats of Formation Substance AHP (kJ/mole) 716.7 CIB) C graphite) C(diamond) CH4(8) C2H2(g) C2H4(8) C2H618) C6H6(e) CHg(e) OIB) 0318) CO2(aq) CO2(g) CO(R) HB) 1.895 -74.81 226.73 52.26 -84.68 49.04 50.0 249.2 143.0 -412.9 -393.5 -110.5 217.9 -241.8 -285.8 -272.0 -825.5 -1121.0 H2O(g) H20le) Fe(s) Fe2O3(s) Fe30413)
need help with 2. Use the following enthalpies of formation to calculate an approximate enthalpy of...
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2. Use the following enthalpies of formation to calculate an approximate enthalpy of reaction, AHrxn for: (5 pts) C3H8 (g) + 502 (g) → 3CO2 (g) + 4 H20 (1) C(s) + O2 (g) - CO2 (g); AH = - 393.5 kJ/mol H2(g) + 42 02 (g) - H20 (1); AH = - 285.5 kJ/mol 3 C(s) + 4 H2(g) → C3H8 (g); AH r = - 103.8 kJ/mol
The combustion of lauric acid is given by the following thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g)...
The combustion of lauric acid is given by the following
thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) +
12 CO2(g) Hcomb is −7377 kJ mol−1 Using the heats of formation
for CO2(g) and H2O(l) calculate the heat of formation (△fH) of
lauric acid. △fH△ CO2(g) = −393.5 kJ mol−1 fH
H2O(l)= −285.8 kJ mol−1
19. The combustion of lauric acid is given by the following thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) + 12 CO2(g) AH...
loab beboo 2CO2 + H2O. 7. Calculate AH for C2H2 +5/202 Given C(s) +O2(g) CO2(g) AH...
loab beboo 2CO2 + H2O. 7. Calculate AH for C2H2 +5/202 Given C(s) +O2(g) CO2(g) AH = -393.5 kJ H2+½ O2 H2O AH= -285.8 kJ 2C+H2 C2H2 AH = 226.8 kJ 008700000 08.0 Lon Qoe cOeEo.O60
Using standard heats of formation calculate AH for 4 FeO (s) + O2 (g) 2 Fe Os (s) AHr of FeO (s) - -272.0 kJ/mol 5 AH'T of Fe2O3 (s) = -825.5 kJ/mol
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) + 6 F2 (g) → 2 CF4(g) + 4 HF (9) can be written as the sum of: CH4 (9) ► 2 C(s) + 2 Ha(o) AH = -52.3 kJ/mol 2 C(s) + 4 Faq) → 2 CF4g) SH -1380 kJ/mol 2 Haq) + 2 Fala) > 4 HF HE.1074 kJimol CsHe(g) + 6 F2 (g) → 2 CF.(g) + 4 HF (g) AH =...
2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5 H2(g) → C2H6 (g) + 2 H2O(g) Compound AH°F (kJ/mol) Compound AH°F (kJ/mol) 52.28 C₂H6 (8) -84.68 C2H4 (8) -393.5 CO2(g) -241.8 H2O(g) -285.9 CO(g) -110.5 H2O(1)
a Using the heats of formation below, calculate the heat of reaction for the following reaction: C2H2(g) + 5/202(2)→ 2C02() +H20() AH® (kJ/mol) C2H2(g) 226.7 O2(g) 0 CO2(g) -393.5 H20(-285.8 kJ Submit b Using the heats of formation below. calculate the heat of reaction for the following reaction: PC13(2) + Cl2(2)→ PC15(e) AH(kJ/mol) PC13(g) -306.4 Cl2(E) 0 PC1s() -398.9
4. If NaHe ()+ Oz (g) Na (g)+ 2 HO (0) Ha (g) +% O (g) H:O (1) Hz (g)+ O2 (g) H2O: () Find AH for N He ()+2 HzO2 (I) N: (g) +4 H2O () AH 622 2 k/mol AH-285 8 kJ/mol AH-187 8 kJ/mol 5. Using standard heats of formation, calculate AH for 4 FeO (s)+ O2 (g) 2 Fe:Os (s) -272.0 kJ/mol AH'r of FeO (s) AH'r of FeaOs (s) = -825.5 kJ/mol 6. Using standard...
1. Find the heat of combustion of liquid toluene (C6H5-CH3) Table of Heats of Formation Substance AHP (kJ/mole) 716.7 CIB) C graphite) C(diamond) CH4(8) C2H2(g) C2H4(8) C2H618) C6H6(e) CHg(e) OIB) 0318) CO2(aq) CO2(g) CO(R) HB) 1.895 -74.81 226.73 52.26 -84.68 49.04 50.0 249.2 143.0 -412.9 -393.5 -110.5 217.9 -241.8 -285.8 -272.0 -825.5 -1121.0 H2O(g) H20le) Fe(s) Fe2O3(s) Fe30413)
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2. Use the following enthalpies of formation to calculate an approximate enthalpy of reaction, AHrxn for: (5 pts) C3H8 (g) + 502 (g) → 3CO2 (g) + 4 H20 (1) C(s) + O2 (g) - CO2 (g); AH = - 393.5 kJ/mol H2(g) + 42 02 (g) - H20 (1); AH = - 285.5 kJ/mol 3 C(s) + 4 H2(g) → C3H8 (g); AH r = - 103.8 kJ/mol
The combustion of lauric acid is given by the following
thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) +
12 CO2(g) Hcomb is −7377 kJ mol−1 Using the heats of formation
for CO2(g) and H2O(l) calculate the heat of formation (△fH) of
lauric acid. △fH△ CO2(g) = −393.5 kJ mol−1 fH
H2O(l)= −285.8 kJ mol−1
19. The combustion of lauric acid is given by the following thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) + 12 CO2(g) AH...
loab beboo 2CO2 + H2O. 7. Calculate AH for C2H2 +5/202 Given C(s) +O2(g) CO2(g) AH = -393.5 kJ H2+½ O2 H2O AH= -285.8 kJ 2C+H2 C2H2 AH = 226.8 kJ 008700000 08.0 Lon Qoe cOeEo.O60
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