2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5...

Question

Question

Answer 1

Answer #1

Q2. Balanced reaction :

2 CO (g) + 5 H2 (g) $\rightarrow$ C2H6 (g) + 2 H2O (g)

enthalpy of reaction, $\Delta$ H = enthalpy of formation of products - enthalpy of formation of reactants

$\Delta$ H = $\Delta$ Ho f (products) - $\Delta$ Ho f (reactants)

$\Delta$ H = [ $\Delta$ Ho f C2H6 (g) + 2 * $\Delta$ Ho f H2O (g)] - [2 * $\Delta$ Ho f CO (g) + 5 * $\Delta$ Ho f H2 (g)]

$\Delta$ H = [(-84.68 kJ/mol) + 2 * (-241.8 kJ/mol)] - [2 * (-110.5 kJ/mol) + 5 * (0)]

$\Delta$ H = -84.68 kJ - 483.6 kJ + 221 kJ

$\Delta$ H = -347.28 kJ

Add a comment

Answer 2

Similar Homework Help Questions

5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2...

5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2 Fe2O3 (s) AH1 of FeO (s) = -272.0 kJ/mol AHºf of Fe2O3 (s) = -825.5 kJ/mol 3. Given 3 C (s) + 4 H2(g) → C3H8 (9) AH = -103.85 kJ/mol C(s) + O2(g) + CO2(g) AH = -393.5 kJ/mol H2 (g) + 12 O2(g) → H2O (1) AH = -285.8 kJ/mol find AH for C3H8 (g) + 5 O2(g) → 3 CO2 (g)...
1. Find the heat of combustion of liquid toluene (C6H5-CH3) Table of Heats of Formation Substance...

1. Find the heat of combustion of liquid toluene (C6H5-CH3) Table of Heats of Formation Substance AHP (kJ/mole) 716.7 CIB) C graphite) C(diamond) CH4(8) C2H2(g) C2H4(8) C2H618) C6H6(e) CHg(e) OIB) 0318) CO2(aq) CO2(g) CO(R) HB) 1.895 -74.81 226.73 52.26 -84.68 49.04 50.0 249.2 143.0 -412.9 -393.5 -110.5 217.9 -241.8 -285.8 -272.0 -825.5 -1121.0 H2O(g) H20le) Fe(s) Fe2O3(s) Fe30413)
for the following rxn Use the standard enthalpies of formation to calculate AH° reaction. C2H4(g) +...

for the following rxn Use the standard enthalpies of formation to calculate AH° reaction. C2H4(g) + H2(g) + C2H6(g) ΔΗ° Substance (kJ/mol) C₂H4 52.4 C2H6 -84.68 0 -32.3 kJ -4.3 x 103 kJ 32.3 kJ 0 -137.1 kJ

Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) +...

Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
C Using the heats of formation below, calculate the heat of reaction for the following reaction:...

C Using the heats of formation below, calculate the heat of reaction for the following reaction: CH4(g) + H2O(g) → C2H5OH(E) AH® (kJ/mol) C2H4(g) 52.26 H2O(g) -241.8 C2H5OH(E) -235.1 kJ d Using the heats of formation below, calculate the heat of reaction for the following reaction: Fe2O3(s) + 2Al(s) - A1203(s) + 2Fe(s) AH(kJ/mol) Fe2O3(s) -824.2 Al(s) 0 Al2O3(s) -1676 Fe(s) 0 KJ
Using the standard heats of formation that follow, calculate the standard enthalpy change for the following...

Using the standard heats of formation that follow, calculate the standard enthalpy change for the following reaction. Species ΔΗΡ(kJ/mol) CO2(g) -393.5 C2H2(g) 226.7 H2O(g)241.8

7. Consider the following reaction: H,(8)+CO,(8)=1,0(g)+CO(g) The value of the equilibrium constant K, for the reaction...

7. Consider the following reaction: H,(8)+CO,(8)=1,0(g)+CO(g) The value of the equilibrium constant K, for the reaction is 0.534 at 700°C. What is the value of K, for this reaction at 298 K? (5 points) (AH; (H20) = -241.8, AH;(CO) = -110.5, AH;(CO2) = -393.5 kJ/mol)
6. Calculate the standard enthal py change for the reaction: CO (g) + H20(g) CO2 (g)...

6. Calculate the standard enthal py change for the reaction: CO (g) + H20(g) CO2 (g) + H2 (g) CO (g) H20 (g) CO2 (g) H2 (g) = -110.5 kJ/mol -241.8 kJ/mol -393.5 kJ/mol O kJ/mol 11 a. +41.2 kJ b.-41.2 kJ c. +82.4 kJ d. -82.4 kJ
a Using the heats of formation below, calculate the heat of reaction for the following reaction:...

a Using the heats of formation below, calculate the heat of reaction for the following reaction: C2H2(g) + 5/202(2)→ 2C02() +H20() AH® (kJ/mol) C2H2(g) 226.7 O2(g) 0 CO2(g) -393.5 H20(-285.8 kJ Submit b Using the heats of formation below. calculate the heat of reaction for the following reaction: PC13(2) + Cl2(2)→ PC15(e) AH(kJ/mol) PC13(g) -306.4 Cl2(E) 0 PC1s() -398.9

Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) +...

Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) + 6 F2 (g) → 2 CF4(g) + 4 HF (9) can be written as the sum of: CH4 (9) ► 2 C(s) + 2 Ha(o) AH = -52.3 kJ/mol 2 C(s) + 4 Faq) → 2 CF4g) SH -1380 kJ/mol 2 Haq) + 2 Fala) > 4 HF HE.1074 kJimol CsHe(g) + 6 F2 (g) → 2 CF.(g) + 4 HF (g) AH =...