Given:
Hof(FeO(s)) = -272.0 KJ/mol
Hof(O2(g)) = 0.0 KJ/mol
Hof(Fe2O3(s)) = -825.5 KJ/mol
Balanced chemical equation is:
4 FeO(s) + O2(g) ---> 2 Fe2O3(s)
ΔHo rxn = 2*Hof(Fe2O3(s)) - 4*Hof( FeO(s)) - 1*Hof(O2(g))
ΔHo rxn = 2*(-825.5) - 4*(-272.0) - 1*(0.0)
ΔHo rxn = -563 KJ
Answer: -563 KJ
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