Consider this reaction: 2C6H6 + 15O2 --> 12CO2 + 6H2O If you start with 1.5 moles of C6H6 and 10 moles of O2, then: how many moles of CO2 can be formed? how many moles of H2O can be formed?
Consider this reaction: 2C6H6 + 15O2 --> 12CO2 + 6H2O If you start with 1.5 moles...
Calculate ΔH∘f (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l) ΔH∘ = -6534kJ ΔH∘f (CO2) = -393.5kJ/mol ΔH∘f (H2O) = - 285.8kJ/mol
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g) --> 12CO2(g)+6H2O(l)+6542kJ If 8.000 g C6H6 is burned and the heat produced from the burning is added to 5692 g of water at 21 C, what is the final temperature of the water? final temperature: _________________ C
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 6.200 g C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘ C, what is the final temperature of the water?
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 5.500 g C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘ C, what is the final temperature of the water?
How many moles of O2 are required to burn completely 63.5 g of C6H6, according to the following equation? 2C6H6 + 15O2 ---> 12CO2 + 6H2O
If 2.73 mol of benzene, C6H6, are reacted with excess oxygen according to 2C6H6+1502- 12CO2 + 6H20 How many grams of CO2 are produced? (Enter your answer to the hundredth place.)
What volume of benzene (C6H6, d=0.88g/ml, molar mass =78.11g/mol) is required to produce 1.5•10*3kj of heat according to the following rxn?: 2C6H6(l) + 15O2(g)—-> 12CO2(g) + 6H2O(g) delta H rxn= -6278kj
5. Benzene reacts with oxygen by the following balanced chemical reaction. 2C6H6(g) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) If 55.0 grams of O2 is reacted with an excess of C6H6 (O2 is the limiting reagent), how many grams of CO2 are produced and how many grams of H2O are produced? (5 points per answer, 10 points total) Grams CO2 Grams H2O cena DOT
Calculate the entropy of the following reaction, using the table below. Enter your answer without units to one decimal. 2C6H6(g) + 15O2 (g) → 12CO2 (g) + 6H2O (g) Substance ΔHf° (kJ/mol) ΔGf° (kJ/mol) S° (J/mol∙K) CH3COOH (g) -484.3 -389.9 159.8 (CH3)2O (g) -184.1 -112.6 266.4 C2H6 (g) -84.0 -32.0 229.2 C2H5OH (g) -234.8 -167.9 281.6 C6H6 (g) 82.9 129.7 269.2 CO2 (g) -393.5 -394.4 213.8 H2O (g) -241.8 -228.6 188.8 H2O (l) -285.8 -237.1 70 O2 (g) 0.0 0.0...
Consider the reaction, C3 H8 + O2 --> CO2 + H2O. How many moles of O2 will react with 9.74 moles of C3 H8?