Question

Calculate ΔHrxn for the following reaction:

5C(s)+6H2(g)→C5H12(l)

Use the following reactions and given ΔH values:

C5H12(l)+8O2(g)→5CO2(g)+6H2O(g),ΔHC(s)+O2(g)→CO2(g),ΔH2H2(g)+O2(g)→2H2O(g),ΔH===−3244.8kJ−393.5kJ−483.5kJ

Express your answer to four significant figures in kilojoules.

Answer 1

50(s)+ 6H (Q) >C5 H12CA) 4 Hr.2 Griven 4H 3244 8 KJ -O c (S) O2G) 4H -393 5 KJ 2 H2C)01 2 H20 () 4H 483.5 KJ Now wriling 2qualion in 5c02)+ GH0 2) - Now dsing aquation x5, We will et 5CC)+502) Now daing quohion x 3 , We wilL aet- GH2a)302a) H20) opposit direction, wa usilt act- 5H12 8029) 4H 3244.8 KJ- 4H 5x-393.5 K) 5 CO2 a) =1967.5 KJ 4H 3x4835K)- - 1450.5 KJ

According to tHess Las, doing 2quation + aqu. 5 Co H0Q) ->C5H2A)+30 4H+3244.8 KJ 5C Cs) +50 GH 301a) 2quM 5coa) AH 1967.5 KJ SOC) 14 50 5 KJ 4H C5H12 (A) 4HYn. = (4H+ 4H + 4H) AH 4H +4H = +3244.8 KJ +(1967.5 K)+ (-1450 5 K) 3244.8 KJ - 1967.5 KJ -1450 5 KJ 73.2 KJ. . The value o 4Hy. in-173.2 K3. A