the combustion of pentane produces heat according to theequation: C5H12(l) + 8O2(g) -->5CO2(g) + 6H2O(l) &nb...

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the combustion of pentane produces heat according to theequation: C5H12(l) + 8O2(g) -->5CO2(g) + 6H2O(l) &nb...

the combustion of pentane produces heat according to theequation:

C₅H₁₂(l) + 8O₂(g) -->5CO₂(g) + 6H₂O(l) ΔH_rxn = -3,510kJ

How many grams of CO₂ are produced per 2,500 kJ ofheat released?

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Answer 1

Answer #1

5 mol CO₂ ==> 3510 kJ of heat
44*5=220 g CO₂ ==> 3510 kJ heat [Because molecularweight of CO2 is 44, which means each mol CO2 weighs 44 g]
1 kJ heat==> 220/3510 g CO₂ = 0.06267 gCO₂
2500 kJ heat==> 0.06267 * 2500 g CO₂ =156.67 gCO₂

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Answer 2

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the combustion of pentane produces heat according to theequation: C5H12(l) + 8O2(g) -->5CO2(g) + 6H2O(l) &nb...

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Calculate ΔHrxn for the following reaction: 5C(s)+6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l)+8O2(g)→5CO2(g)+6H2O(g),...

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the combustion of pentane produces heat according to theequation: C5H12(l) + 8O2(g) -->5CO2(g) + 6H2O(l) &nb...

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Add Answer to: the combustion of pentane produces heat according to theequation: C5H12(l) + 8O2(g) -->5CO2(g) + 6H2O(l) &nb...

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the combustion of pentane produces heat according to theequation: C5H12(l) + 8O2(g) -->5CO2(g) + 6H2O(l) &nb...