Question

Pentane (C5H12) burns in oxygen to produce carbon dioxide and water via the following reaction: C5H12(g)+8O2(g))...

Pentane (C5H12) burns in oxygen to produce carbon dioxide and water via the following reaction: C5H12(g)+8O2(g)) Δ⟶ 5CO2(g)+6H2O(g)

Calculate the mass of CO2 that can be produced if the reaction of 36.5 g of pentane and sufficient oxygen has a 65.0 % yield.

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Answer #1

- CS HR + 802 (9) - 50 + 6H 0 (9) mans of pentane = 36-59 Molar man of Pentane = 1285-412X1 60+62272g/mole no. of moles of VLNow, Molar mass of lą o 127 1682 = 44g/moto. so mass of co2 produced = 1647 X 444 z ape (65% yield) is present 72.59 roubare

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