Question

Calculate ΔHrxn for the following reaction:

5C(s)+6H2(g)→C5H12(l)

Use the following reactions and given ΔH values:

C5H12(l)+8O2(g)→5CO2(g)+6H2O(g), ΔH= -3244.8 kJ

C(s)+O2(g)→CO2(g), ΔH= -393.5 kJ

2H2(g)+O2(g)→2H2O(g), ΔH= -483.5 kJ

Answer 1

Answer C5 H12 (1) +806) → 560,69) + 6H209) - © SH= -3244.8K1 CC) + 02 (6) 02 (69) - OH = -393.5kj. 2420) + 029) > 24209) —W SH =-483-50 We have to calentate Shoxn for the following reaction. 56 (5) + 6H2(g) → Cg H12 (1) Now, ② x 5 we have 50(5) +502 (9) →5602 (9) — AH = -393.5K3 X5 = -1967.5 kJ and 11 X3 we have 6H2 9) + 3020) + 6H20(g) ♡ AH = -4835x3 kg. + We have = -1450.56] now, ge(s) + 6H2 (%) +802(3) → 5669 (9) + 6H20 (3) - OH = -1967.5+41457.5)) Kg = - 3418 kg CS Scanned with Cam Scanner

Now @ -6 we have 50(5) + 6 Hz (9) +80, (9- C5H12 (1) - 80290 5602g) +6 H20 (9) - 5602 (9) — 6 H20 (9) W, 50(5) +6 Hz @9 → C5 H2 609 H = 3418K) – (-32441867) = -3418 kJ +324458 RJ = -173.2 R1 ran. . Hran = -173.2 Kg CS Scanned with CamScanner