Calculate delta Hrxn for the following reaction:
5C(s)+6H2(g)--->C5H12(l)
RXN1 = C5H12(l)+8O2(g)---> 5CO2(g)+6H2O(g)
delta H= -3505.8 kJ
RXN2 = C(s)+O2(g)--->CO2(g) delta H=
-393.5 kJ
RXN3 = 2H2(g)+O2(g)---> 2H2O(g)
delta H= -483.5 kJ
a) we need 5C(s) on the left, so multiply RXN 2 by 5
5C(s) + 5O2(g) = 5 CO2(g) H = 5(-393.5) = -1967.5 kJ
b) we need C5H12 on ht right side, so invert rxn 1
5CO2(g)+6H2O(g) ---> C5H12(l)+8O2(g) H= 3505.8 kJ
add both equations
5C(s) + 5O2(g) + 5CO2(g)+6H2O(g) ---> C5H12(l)+8O2(g)+5 CO2(g) H = -1967.5 +3505.8 = 1538.3
simplify
5C(s) + 5O2(g) + 6H2O(g) ---> C5H12(l)+8O2(g) H = 1538.3
we need 6H2 on the lef tside, so mult8iply RXN 3 by3
6H2(g)+3O2(g)---> 6H2O(g) delta H= 3*(-483.5) = -1450.5
add rxn
6H2(g)+3O2(g) + 5C(s) + 5O2(g) + 6H2O(g) ---> C5H12(l)+8O2(g)+6H2O(g) H = 87.8
simplify
6H2(g)+5C(s) ---> C5H12(l) H = 87.8
order
5C(s) + 6H2(g) = C5H12(l) H = 87.8 kJ/mol
The fist step to solve this equation is to arrange the equations according to the place where you want them, for the first equation you have the C5H12 on the left side, you actually want it on the product side so the best thing to do is to invert the first equation
5CO2(g)+6H2O(g) ---> C5H12(l)+8O2(g) H= 3505.8 kJ
You want 5 carbons on the left side, so you have to multiply by 5 the second equation, you have to multiply all the elements also you have to multiply by 5 the enthalpy provided
5 C(s)+ 5 O2(g)---> 5 CO2(g) H= -1967.5 kJ
You want 6 H2 in the overall equation, you have 2 H2 in equation 3, you have to multiply by 3 the equation to get 6H2 so:
6 H2(g)+3 O2(g)---> 6 H2O(g) H= -1450.5 kJ
Now add the three equation
5CO2(g)+6H2O(g) ---> C5H12(l)+8O2(g)
5 C(s)+ 5 O2(g)---> 5 CO2(g)
6 H2(g)+3 O2(g)---> 6 H2O(g)
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5 C + 6 H2 + 8O2 + 5CO2 + 6H2O C5H12(l)+ 8O2 + 5CO2 + 6H2O
The underlined elements are repeated on both sides so you can remove it to make a net equation
5 C + 6 H2 C5H12(l)
Our procedure is correct, similarly you have to add all the values to get the enthalpy you want to find:
3505.8 + (-1967.5) + (-1450.5) = 87.8 KJ / mol
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