Determine Heat of reaction (Hrxn) for: 2 C (s, graphite) + 3 H2 (g) ------> C2H6 (g) from the following
C (s, graphite) + O2 (g) ------> CO2 (g) delta H = -393.5 kJ
H2 (g) + 1/2 O2 (g) ------> H2O (l) delta H = -285.8 kJ
2 C2H6 (g) + 7 O2 (g) ------> 6 H2O (l) + 4 CO2 (g) delta H = -3,119.6 kJ
Determine Heat of reaction (Hrxn) for: 2 C (s, graphite) + 3 H2 (g) ------> C2H6...
Use the following information to calculate the heat of formation of propane C3H8. 3 C (S-Graphite) + 4 H2 (g) —› C3H8 (g) 1. C (S-Graphite) + O2 (g) —› CO2 (g) ΔH = - 393.5 kJ 2. H2 (g) + ½ O2 (g) —› H2O (l) ΔH = - 285.8 kJ 3. C3H4 (g) + 4 O2 (g) —› 3 CO2 (g) + 2 H2O (l) ΔH = - 1937 kJ 4. C3H6 (g) + 9/2 O2 (g) —›...
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ/mol reaction (2): H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ/mol reaction (3): 2 C(s) + 3 H2(g) → C2H6(g) ΔH = −84.0 kJ/mol
Reaction of 6.300 grams of C2H6(g) according to the reaction below released 327.6 kJ of heat. What is the ?H of the reaction? 2 C2H6(g) + 7 O2(g) ---> 4 CO2(g) + 6 H2O(l) ?Hrxn = ?
Please explain
Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
Use the Data table to calculate ∆H for the reaction below:Reactions: Change in Enthalpy (∆H)(1) C (s) + O2 (g) -> CO2(g) ∆H1 = -393.5 kJ/ mol(2) H2 (g) + 1/2 O2 (g) -> H2O (l) ∆H2 = -285.8 kJ/mol(3) 2C2H6 (g) + 7O2 (g) -> 4 CO2 (g) + 6 H2O (l) ∆H3 = -283.0 kJ/molCalculate the enthalpy change for the reaction:2 C (s) + 3 H2 (g) -> C2H6(g) ∆H = ______________kJ/mol
From the following data, C(graphite) + O2(g) → CO2(g) AHrxn = -393.5 kJ/mol H2(g) + O2(g) → H200) AH"rxn = -285.8 kJ/mol 2C2H6(g) + 702(g) -> 4CO2(g) + 6H2O(l) Arxn=-3119.6 kJ/mol Calculate the enthalpy change for the reaction: 2 C(graphite) + 3H2(g) + C2H668)
1. Calculate AH for the reaction C2H4 (8) + H2() → C2H6), from the following data. C2H4 (g) + 3 02 (®) → 2 CO2 (s) + 2 H20 (1) C2H6 (g) + 7/2 02(g) → 2 CO2(g) + 3 H20 (1) H2 + 1/2O2() → H20 (1) AH = -1411. kJ/mole AH = -1560. kJ/mole AH = -285.8 kJ/mole 2. Calculate AH for the reaction 4 NH3(g) +502 (g) → 4 NO(g) + 6 H20 (g), from the following...
Consider the following data. 2 C(s) + H2(g) C2H2(g) H = +226.8 kJ CO2(g) C(s) + O2(g) H = +393.5 kJ 2 H2O(l) 2 H2(g) + O2(g) H = +571.7 kJ Use Hess's law to calculate H for the reaction below. 2 C2H2(g) + 5 O2(g) 4 CO2(g) + 2 H2O(l) find kJ
Consider the following data.
CH4(g) C(s) + 2 H2(g)
H = +74.8 kJ
C(s) + O2(g)
CO2(g)
H = -393.5 kJ
2 H2(g) +
O2(g) 2 H2O(l)
H = -571.7 kJ
Use Hess's law to calculate H for the reaction below.
CH4(g) + 2 O2(g) CO2(g) + 2 H2O(l)
H = _____ kJ
Calculate delta Hrxn for the following reaction: 5C(s)+6H2(g)--->C5H12(l) use the following reactions and given delta H's: C5H12(l)+8O2(g)---> 5CO2(g)+6H2O(g) delta H= -3505.8 kJ C(s)+O2(g)--->CO2(g) delta H= -393.5 kJ 2H2(g)+O2(g)---> 2H2O(g) delta H= -483.5 kJ The steps to solving this problem would be greatly appreciated! Thanks so much!