Use the following information to calculate the heat of formation of propane C3H8. 3 C (S-Graphite)...
Use the following information to calculate the heat of formation
of propane C3H8.
3 C (S-Graphite) + 4 H2 (g) —› C3H8 (g)
1. C (S-Graphite) + O2 (g) —› CO2 (g) ΔH = - 393.5 kJ
2. H2 (g) + ½ O2 (g) —› H2O (l) ΔH = - 285.8 kJ
3. C3H4 (g) + 4 O2 (g) —› 3 CO2 (g) + 2 H2O (l) ΔH = - 1937 kJ
4. C3H6 (g) + 9/2 O2 (g) —› 3 CO2 (g) + 3 H2O (g) ΔH = - 2007 kJ
5. C3H8 (g) + 5 O2 (g) —› CO2 (g) + 4 H2O (l) ΔH = - 2219.1 kJ
Homework Answers
1. C (S-Graphite) + O2 (g) —› CO2 (g) ΔH = - 393.5 kJ --------> 1
2. H2 (g) + ½ O2 (g) —› H2O (l) ΔH = - 285.8 kJ --------------> 2
3. C3H4 (g) + 4 O2 (g) —› 3 CO2 (g) + 2 H2O (l) ΔH = - 1937 kJ --------------> 3
4. C3H6 (g) + 9/2 O2 (g) —› 3 CO2 (g) + 3 H2O (g) ΔH = - 2007 kJ -------------> 4
5. C3H8 (g) + 5 O2 (g) —› CO2 (g) + 4 H2O (l) ΔH = - 2219.1 kJ -------------> 5
equation 1 multifly with 3 and equation 2 multifly with 4
3C (S-Graphite) + 3O2 (g) —› 3CO2 (g) ΔH = - 1180.5 kJ --------> 1
4 H2 (g) + 2 O2 (g) ---------------> 4H2O (l) ΔH = - 1143.2kJ --------------> 2
----------------------------------------------------------------------------------------------------------------
3C( S-Graphite) + 4H2(g) + 5O2(g) ----------> 3CO2(g) + 4H2O(l) ΔH = -2323.69KJ
C3H8 (g) + 5 O2 (g) ----------------->3CO2 (g) + 4 H2O (l) ΔH = - 2219.1 kJ ---------> 5 subtract
(-) (-) (-) (-) (+)
--------------------------------------------------------------------------------------------------------------------------------------
3 C (S-Graphite) + 4 H2 (g)-----------------------------> C3H8 (g) ΔH = -104.59KJ
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Use the following information to calculate the heat of formation
of propane C3H8.
3 C (S-Graphite)...
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g)...
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) -- 3 CO2(g) + 4H2O(g) Arxn = -2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3H8 a. -104.7 kJ/mol ob. +1407.7 kJ/mol C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol
The combustion of propane, C3H8, occurs via the reaction C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) with heat of formation values given...
The combustion of propane, C3H8, occurs via the reaction C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) with heat of formation values given by the following table: Substance ΔH∘f (kJ/mol) C3H8 (g)= -104.7 CO2(g)= −393.5 H2O(g)= −241.8 Calculate the enthalpy for the combustion of 1 mole of propane.
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PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2...
5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2 Fe2O3 (s) AH1 of FeO (s) = -272.0 kJ/mol AHºf of Fe2O3 (s) = -825.5 kJ/mol 3. Given 3 C (s) + 4 H2(g) → C3H8 (9) AH = -103.85 kJ/mol C(s) + O2(g) + CO2(g) AH = -393.5 kJ/mol H2 (g) + 12 O2(g) → H2O (1) AH = -285.8 kJ/mol find AH for C3H8 (g) + 5 O2(g) → 3 CO2 (g)...
Combustion of 2.5000 g of propane (C3H8) releases 115.75 kJ of heat when it is burned...
Combustion of 2.5000 g of propane (C3H8) releases 115.75 kJ of heat when it is burned to form CO2 (g) and H2O (l). The standard formation enthalpies of CO2 (g) and H2O (l) are -393.5 kJ/mol and -285.5 kJ/mol respectively. Calculate the Hrxn for the combustion of propane in kJ/mol Calculate ∆?? ? for propane
Given the following heat of formation values, calculate the heat of reaction for the following: C3H8(g)...
Given the following heat of formation values, calculate the heat of reaction for the following: C3H8(g) + O2(g) CO2(g) + H2O(1). AfH values in kJ/mol: C3H8(g): -103.8, O2(g): 0, CO2(g): -393.5, H2O(l): -285.8. 3.613 x 102 kJ/mol -2.220 103 kJ/mol 1.413* 102 kJ/mol -5.755 x 102 kJ/mol If a lighter contains 4.0 mL of liquid butane (density of butane = 0.8 g/cm3), how much heat can we get out of it, from the combustion of butane? 2 C4H 10(g) +...
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Part 1) Use the following equations to calculate the heat of the reaction for the formation of ethane (C2H6). C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3 H2O(l) ∆ Ho = -1560 kJ C(gr) + O2(g) → CO2(g) ∆ Ho = -394 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆ Ho = -286 kJ Calculate ∆Ho for the following reaction: 2 C(gr) + 3H2(g) → C2H6(g) ethane Use kJ for your answer. ΔHo = Part 2) Find the heat of...
Use Hess's law to determine A.Hº for the reaction C3H4(g) + 2 H2(g) -> C3H8(8), given that Hy(8) + O2(8) — H2O(1) A...
Use Hess's law to determine A.Hº for the reaction C3H4(g) + 2 H2(g) -> C3H8(8), given that Hy(8) + O2(8) — H2O(1) A Hº = -285.8 kJ mol-1 C3H4(8) + 402(g) — 3 CO2(g) + 2 H2O(1) A Hº = -1937 kJ mol-1 C3H2(g) + 5O2(g) — 3CO2(g) + 4H2O(1) A Hº = -2219.1 kJ mol-1
Using the following equation for the combustion of propane, calculate the amount of propane consumed if...
Using the following equation for the combustion of propane, calculate the amount of propane consumed if the reaction gave off 333 kJ heat. C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(g) ΔH = -2044 kJ
Use the following data to calculate the standard enthalpy of formation of heptane, C7H16 (l). C7H16...
Use the following data to calculate the standard enthalpy of formation of heptane, C7H16 (l). C7H16 (l) + 11 O2 (g → 7 CO2 (g) + 8 H2O (l) ΔH° = -4817 kJ/mol ΔHf° of CO2 (g) = -393.5 kJ/mol ΔHf° of H2O (l) = -285.8 kJ/mol A)-218.2 kJ/mol B)-468.1 kJ/mol C)-223.9 kJ/mol D)-447.8 kJ/mol E)-111.5 kJ/mol
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) -- 3 CO2(g) + 4H2O(g) Arxn = -2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3H8 a. -104.7 kJ/mol ob. +1407.7 kJ/mol C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol
PROBLEM-SOLVING CLASS ACTIVITY 11 Use Hess's Law to calculate the enthalpy of formation of CH2OH: C(graphite) + 2 H2(g) + 1026) → CH2OH(1) Given the following data: CH2OH() • 02(9) + CO2(g) + 2H2O(1) AH°: -726.4 kJ/mol C(graphite). O2(g) → CO2(9) AH' = -393.5 kJ/mol H2(g) + 40269) → H2O(1) AH = -285.8 kJ/mol
5. Using standard heats of formation, calculate AH for 4 FeO (s) + O2(g) → 2 Fe2O3 (s) AH1 of FeO (s) = -272.0 kJ/mol AHºf of Fe2O3 (s) = -825.5 kJ/mol 3. Given 3 C (s) + 4 H2(g) → C3H8 (9) AH = -103.85 kJ/mol C(s) + O2(g) + CO2(g) AH = -393.5 kJ/mol H2 (g) + 12 O2(g) → H2O (1) AH = -285.8 kJ/mol find AH for C3H8 (g) + 5 O2(g) → 3 CO2 (g)...
Given the following heat of formation values, calculate the heat of reaction for the following: C3H8(g) + O2(g) CO2(g) + H2O(1). AfH values in kJ/mol: C3H8(g): -103.8, O2(g): 0, CO2(g): -393.5, H2O(l): -285.8. 3.613 x 102 kJ/mol -2.220 103 kJ/mol 1.413* 102 kJ/mol -5.755 x 102 kJ/mol If a lighter contains 4.0 mL of liquid butane (density of butane = 0.8 g/cm3), how much heat can we get out of it, from the combustion of butane? 2 C4H 10(g) +...
Use Hess's law to determine A.Hº for the reaction C3H4(g) + 2 H2(g) -> C3H8(8), given that Hy(8) + O2(8) — H2O(1) A Hº = -285.8 kJ mol-1 C3H4(8) + 402(g) — 3 CO2(g) + 2 H2O(1) A Hº = -1937 kJ mol-1 C3H2(g) + 5O2(g) — 3CO2(g) + 4H2O(1) A Hº = -2219.1 kJ mol-1
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