1. Calculate AH for the reaction C2H4 (8) + H2() → C2H6), from the following data....
(2) ( 2 points ) Compute AH for the reaction, 2 CH4 + C2H4(9) + 2 H2(g) given the following data: H2(g) + } 02(g) + H20(1) AH° = -285.8 kJ CO2(g) + 2 H2O(l) + CH4(g) + 2 029) AH° = 890.3 kJ 2 C2H6(g) + 7 02(g) + 4CO2(g) + 6 H2O(1) AH° = -3120.8 kJ C2H4(9) + H2(g) → C2H6(9) AH° = -136.3 kJ
1) C2H6 (g) -----> C2H4 (g) + H2 (g) ΔH1 = ? 2) C2H6 (g) + 3.5O2 (g) -----> 2CO2 (g) + 3H2O (l) ΔH2 = -1560 kJ/mo 3) C2H4 (g) + 3O2 (g) -----> 2CO2 (g) + 2H2O (l) ΔH3 = -1411 kJ/mol 4) 2H2O (l) -----> 2H2 (g) + O2 (g) ΔH4 = 571.6 kJ/mol How much heat is transferred between the system and the surroundings when 25 grams of ethane (C2H6) decomposes to produce ethylene (C2H4) and...
Part 1) Use the following equations to calculate the heat of the reaction for the formation of ethane (C2H6). C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3 H2O(l) ∆ Ho = -1560 kJ C(gr) + O2(g) → CO2(g) ∆ Ho = -394 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆ Ho = -286 kJ Calculate ∆Ho for the following reaction: 2 C(gr) + 3H2(g) → C2H6(g) ethane Use kJ for your answer. ΔHo = Part 2) Find the heat of...
You are given the following data. AH = = -286.0 kJ H2(g) + 1/2O2(g) → H20(1) N2O5(9) + H20(1) → 2 HNO3(aq) 1/2 N2(9) + 3/2 02(9) + 1/2 H2(9) AH = -77.0 kJ HNO3(1) AH = -174.0 kJ Calculate the AH for the reaction given below. 2 N2(g) + 5 O2(g) → 2 N205(9) k] Need Help? Read It Supporting Materials Periodic Table E Constants & Factors Supplemental Data
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
show steps • What is the AH for the reaction: 2N2(g) + 502(9) -> 2N205 H2(g) + 12 Oz(9) -> H20(1) AH = -285.8 kJ N2O3(9) + H20 (1) -> 2HNO3 (1) AH = -76.6 kJ N2(g) + 302(g) + H2(g) -> 2HNO3 (1) AH = -348.2 kJ Click to add notes
Given the following equations and AH' values: C(s) + O2(g) + CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) - H20 (1) AH = -285.8 kJ 2C2H2 (8) + 5O2(g) + 4CO2(g) + 2H20 (1) AH'= -2598 kJ Determine the heat of reaction (in kJ) at 298 K for the reaction: 2C(s) + H2(8) C2H2 (8) 0-136.8 0-219.8 0-109.9 O-167.1 +226.2
DaC. NUL20 1) Find AH, for the reaction 2H2(g) + 2C(s) + O2(g) → C2H5OH(I), using the following thermochemical data. For Hess's Law, rewrite equations to find out AH. C2H5OH (1) +2 02 (g) → 2 CO2 (g) + 3H20 (1) AH = -875.J C(s) + O2(g) → CO2 (g) AH = -394,51 kJ H2(g) + 12 02 (g) → H20 (1) AH = -285.8 kJ
2) From the enthalpies of reaction provided, calculate the AH for the reaction of carbon with hydrogen as shown below. Is the reaction exothermic or endothermic? How many grams of C3Hg are produced with an enthalpy change of 209.4 kJ? 3 C(s) + 4 H2(g) - C He(a) moto-non (5+3=2 C3H8(9) + 5 O2(g) 3 CO2(g) + 4 H2O(9) AH = -2043 kJ/mol AH = -393.5 kJ/mol C(s) + Ozon 2 H2(g) + O2th CO2(g) 2 H20(9) AH = -483.6...