Question

(2) ( 2 points ) Compute AH for the reaction, 2 CH4 + C2H4(9) + 2 H2(g) given the following data: H2(g) + } 02(g) + H20(1) AH° = -285.8 kJ CO2(g) + 2 H2O(l) + CH4(g) + 2 029) AH° = 890.3 kJ 2 C2H6(g) + 7 02(g) + 4CO2(g) + 6 H2O(1) AH° = -3120.8 kJ C2H4(9) + H2(g) → C2H6(9) AH° = -136.3 kJ

Answer 1

2 CH - Ety & 22 AH = ? in - CH4 + 20 AH = 890.3 kJ Reverse the above reaction and multiply with a sign of Ato changes from tive to uve 2 CH4 + 402 - 2 Co, +4H20 AH =-1780.6 kJ → "Lg) (g) 19 (1) G H & H₂ - St. At =-136-3kJ Reverse the above reaction signat AH changes from are TO tove cho -> Ç HA + H2 AH = +136.3 kJ → g) (9) 24 Hot 20 - 4CO2 + 64o.. HL-3120-85 -39 ta (9) Reverse the above reaction and divide with 2 sign of Ho changes from ove to tve 2CO2 + HO -> EHE+4H - +1560-465> 19) (9) Hingst 50%) >420129 th = - 285.865 Reverse the above reaction sign of AH changes from the to ave (9) AH = +285.8 kJ ~ How - H₂ + + 2 19 4H = -1780.6k5 2 CH2 +48 200 444 AH = +1560-465 Elfego - sita gst Hugo 4 H = + 136.3 kJ 2.96mlyst 367460 - St6.gst 38 Halle) - Hugot the AH = +285.8k5 city - stuggt 24 AH AH AH AH AH = 201.9ks