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![Combustion reaction of propane - = [(3 x-393.5) +(4 X-285-8)] - [(5x0) + (-103-8)] kJ/mol 51 - 180.5 – 1143-2] - [-103.8) - 2](http://img.homeworklib.com/questions/afd50dc0-730d-11ea-a0de-87559ad11e0c.png?x-oss-process=image/resize,w_560)
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16. + -/2 points was OSGenChem1 5.3.WA.033.0/10 Submissions Used The combustion reaction of propane is as...
11. -/2 points was OSGenChem1 5.3.WA.010.0/10 Submissions Used Given that AH = -571.6 kJ/mol for the...
11. -/2 points was OSGenChem1 5.3.WA.010.0/10 Submissions Used Given that AH = -571.6 kJ/mol for the reaction 2 H2(g) + 0,(g) → 2 H20(i), calculate AH for these reactions. (a) 2 H20(1) - 2H2(g) + O2(9) kJ/mol (6) 49 H (9) + 1/2 0,(9) H,00) kJ/mol (c) 427 6 H20(1) 6 H2(g) + 3 0 (9) kJ/mol Need Help? 12. 2/2 points Previous Answers was OSGenchem 1 5.3.WA.032. 1/10 Submissions Used how many moles of water are present if 53.8...
13 Question (3 points) The enthalpy change for a chemical reaction is the sum of the...
13 Question (3 points) The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize Part 1 (1 point) Il See Periodic Table...
| 10. + -1 points ChangWA12 6.СМ.011. My Notes Ask Your Teacher The combustion reaction of...
| 10. + -1 points ChangWA12 6.СМ.011. My Notes Ask Your Teacher The combustion reaction of butane is as follows. C4H10(9)13/2 02(9)-4 CO2(g) 5 H20(0) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g)-. CO2(g) reaction (2): 21/2 02(9) H20UAH--285.8 kJ/mo reaction (3): 4 C(s) + 5 H2(g)- + C4H10(g) H-_1257 krmol H--393.5 kJ/mol kJ/mol Supporting Materials Periodic Table Constants and Factors Supplemental Data
The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking...
The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize 3rd attempt See Hint Ad See Periodic Table Part 1 (1 point)...
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) +...
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ/mol reaction (2): H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ/mol reaction (3): 2 C(s) + 3 H2(g) → C2H6(g) ΔH = −84.0 kJ/mol
Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) +...
Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) + 3 CO2(g) + 4 H20(1) AH° = -2219.9 kJ C(s) + O2(g) + CO2(8) AH° = -393.5 kJ 2 H2(g) + O2 + 2 H2O(1) AH° = -571.6 kJ Calculate the enthalpy of formation of propane. The reaction is shown below. 3 C(s) + 4H2(g) → C3H3(g)
Calculate the AH formation of octane, CBH1B (), given that the enthalpy of combustion of octane...
Calculate the AH formation of octane, CBH1B (), given that the enthalpy of combustion of octane is -5471 kl/mol and the standard enthalpies of formation of H20 () and CO2 (g) are -393.5 kJ/mol and -285.8 kJ/mol respectively.
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g)...
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
4. (3 points) Consider the following enthalpies of reaction: CaCz(s) + 2H20 (Ca(OH)2(s) + CH2(g) AH,º=-127.9...
4. (3 points) Consider the following enthalpies of reaction: CaCz(s) + 2H20 (Ca(OH)2(s) + CH2(g) AH,º=-127.9 kJ/mol Cas) + 1/20 (g) - Cao(s) AH,º=-635.1 kJ/mol Cal(s) + H200 - Ca(OH) (9) AH,=-65.2 kJ/mol The standard enthalpies of combustion of graphite and C2H2(g) are -393.51 and -1299.58 kJ/mol, respectively. Calculate the standard enthalpy of formation of CaCz(s) at 25°C. Aside on enthalpy of combustion: Please note that the standard enthalpy of combustion will form H200, not H:09), if the substance includes...
need help with 2. Use the following enthalpies of formation to calculate an approximate enthalpy of...
need help with
2. Use the following enthalpies of formation to calculate an approximate enthalpy of reaction, AHrxn for: (5 pts) C3H8 (g) + 502 (g) → 3CO2 (g) + 4 H20 (1) C(s) + O2 (g) - CO2 (g); AH = - 393.5 kJ/mol H2(g) + 42 02 (g) - H20 (1); AH = - 285.5 kJ/mol 3 C(s) + 4 H2(g) → C3H8 (g); AH r = - 103.8 kJ/mol
11. -/2 points was OSGenChem1 5.3.WA.010.0/10 Submissions Used Given that AH = -571.6 kJ/mol for the reaction 2 H2(g) + 0,(g) → 2 H20(i), calculate AH for these reactions. (a) 2 H20(1) - 2H2(g) + O2(9) kJ/mol (6) 49 H (9) + 1/2 0,(9) H,00) kJ/mol (c) 427 6 H20(1) 6 H2(g) + 3 0 (9) kJ/mol Need Help? 12. 2/2 points Previous Answers was OSGenchem 1 5.3.WA.032. 1/10 Submissions Used how many moles of water are present if 53.8...
13 Question (3 points) The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize Part 1 (1 point) Il See Periodic Table...
| 10. + -1 points ChangWA12 6.СМ.011. My Notes Ask Your Teacher The combustion reaction of butane is as follows. C4H10(9)13/2 02(9)-4 CO2(g) 5 H20(0) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g)-. CO2(g) reaction (2): 21/2 02(9) H20UAH--285.8 kJ/mo reaction (3): 4 C(s) + 5 H2(g)- + C4H10(g) H-_1257 krmol H--393.5 kJ/mol kJ/mol Supporting Materials Periodic Table Constants and Factors Supplemental Data
The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize 3rd attempt See Hint Ad See Periodic Table Part 1 (1 point)...
Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) + 3 CO2(g) + 4 H20(1) AH° = -2219.9 kJ C(s) + O2(g) + CO2(8) AH° = -393.5 kJ 2 H2(g) + O2 + 2 H2O(1) AH° = -571.6 kJ Calculate the enthalpy of formation of propane. The reaction is shown below. 3 C(s) + 4H2(g) → C3H3(g)
Calculate the AH formation of octane, CBH1B (), given that the enthalpy of combustion of octane is -5471 kl/mol and the standard enthalpies of formation of H20 () and CO2 (g) are -393.5 kJ/mol and -285.8 kJ/mol respectively.
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
4. (3 points) Consider the following enthalpies of reaction: CaCz(s) + 2H20 (Ca(OH)2(s) + CH2(g) AH,º=-127.9 kJ/mol Cas) + 1/20 (g) - Cao(s) AH,º=-635.1 kJ/mol Cal(s) + H200 - Ca(OH) (9) AH,=-65.2 kJ/mol The standard enthalpies of combustion of graphite and C2H2(g) are -393.51 and -1299.58 kJ/mol, respectively. Calculate the standard enthalpy of formation of CaCz(s) at 25°C. Aside on enthalpy of combustion: Please note that the standard enthalpy of combustion will form H200, not H:09), if the substance includes...
need help with
2. Use the following enthalpies of formation to calculate an approximate enthalpy of reaction, AHrxn for: (5 pts) C3H8 (g) + 502 (g) → 3CO2 (g) + 4 H20 (1) C(s) + O2 (g) - CO2 (g); AH = - 393.5 kJ/mol H2(g) + 42 02 (g) - H20 (1); AH = - 285.5 kJ/mol 3 C(s) + 4 H2(g) → C3H8 (g); AH r = - 103.8 kJ/mol
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