Homework Answers
We can get the formation of propane equation as
3x equation 2 + 2 x equation 3 - equation 1
Thus
Delta Hf of propane = [3x delat H c of C + 2 x delta Hc of H2 - delta Hc of propane]
= [ 3(-393.5) + 2(-571.6) - (-2219.9)] kJ
= - 103.8 kJ /mole
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Given the enthalpies of combustion of propane (C3Hg), carbon and hydrogen, C3H3(g) + 5 O2(g) +...
2) From the enthalpies of reaction provided, calculate the AH for the reaction of carbon with hydrogen as shown bel...
2) From the enthalpies of reaction provided, calculate the AH for the reaction of carbon with hydrogen as shown below. Is the reaction exothermic or endothermic? How many grams of C3Hg are produced with an enthalpy change of 209.4 kJ? 3 C(s) + 4 H2(g) - C He(a) moto-non (5+3=2 C3H8(9) + 5 O2(g) 3 CO2(g) + 4 H2O(9) AH = -2043 kJ/mol AH = -393.5 kJ/mol C(s) + Ozon 2 H2(g) + O2th CO2(g) 2 H20(9) AH = -483.6...
Question 3 Propane (C3Hg) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g)...
Question 3 Propane (C3Hg) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) - 3 CO2(g) + 4H2O(g) AHrxn=-2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3Hg a. -104.7 kJ/mol O b. +1407.7 kJ/mol O C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol uestion 4 Consider the evaporation of liquid water to water vapor at 125°C. What is true...
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g)...
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g)...
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) -- 3 CO2(g) + 4H2O(g) Arxn = -2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3H8 a. -104.7 kJ/mol ob. +1407.7 kJ/mol C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol
16. + -/2 points was OSGenChem1 5.3.WA.033.0/10 Submissions Used The combustion reaction of propane is as...
16. + -/2 points was OSGenChem1 5.3.WA.033.0/10 Submissions Used The combustion reaction of propane is as follows. CHg(9) + 5 02(9) ► 3 CO2(g) + 4 H2O(1) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(9) + CO2(g) | AH = -393.5 kJ/mol reaction (2): H2(9) + 1/2 02(g) → H200 AH = -285.8 kJ/mol reaction (3): 3 C(s) + 4 H (9) CHg(9) AH = -103.8...
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) +...
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ/mol reaction (2): H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ/mol reaction (3): 2 C(s) + 3 H2(g) → C2H6(g) ΔH = −84.0 kJ/mol
need help with 2. Use the following enthalpies of formation to calculate an approximate enthalpy of...
need help with
2. Use the following enthalpies of formation to calculate an approximate enthalpy of reaction, AHrxn for: (5 pts) C3H8 (g) + 502 (g) → 3CO2 (g) + 4 H20 (1) C(s) + O2 (g) - CO2 (g); AH = - 393.5 kJ/mol H2(g) + 42 02 (g) - H20 (1); AH = - 285.5 kJ/mol 3 C(s) + 4 H2(g) → C3H8 (g); AH r = - 103.8 kJ/mol
Combustion of 2.5000 g of propane (C3H8) releases 115.75 kJ of heat when it is burned...
Combustion of 2.5000 g of propane (C3H8) releases 115.75 kJ of heat when it is burned to form CO2 (g) and H2O (l). The standard formation enthalpies of CO2 (g) and H2O (l) are -393.5 kJ/mol and -285.5 kJ/mol respectively. Calculate the Hrxn for the combustion of propane in kJ/mol Calculate ∆?? ? for propane
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values...
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values for reactions at 25°C, what is AH at 25°C for the following reaction: C3H3(g) + 502(g) + 4H2O(g) + 3CO2(g) AH = -2043 kJ 3C(s) + 4 H2(g) → C3H8 (g) 2H2(g) + O2(g) + 2H2O(g) AH° = -483.6 kJ
The thermochemical equation for the combustion of propane is: C3H8 (g) + 5 O2 (g) ...
The thermochemical equation for the combustion of propane is: C3H8 (g) + 5 O2 (g) 3 CO2 (g) + 4 H2O (l) H = -2220 kJ What is the enthalpy change when 35.0 g of propane react?
2) From the enthalpies of reaction provided, calculate the AH for the reaction of carbon with hydrogen as shown below. Is the reaction exothermic or endothermic? How many grams of C3Hg are produced with an enthalpy change of 209.4 kJ? 3 C(s) + 4 H2(g) - C He(a) moto-non (5+3=2 C3H8(9) + 5 O2(g) 3 CO2(g) + 4 H2O(9) AH = -2043 kJ/mol AH = -393.5 kJ/mol C(s) + Ozon 2 H2(g) + O2th CO2(g) 2 H20(9) AH = -483.6...
Question 3 Propane (C3Hg) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) - 3 CO2(g) + 4H2O(g) AHrxn=-2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3Hg a. -104.7 kJ/mol O b. +1407.7 kJ/mol O C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol uestion 4 Consider the evaporation of liquid water to water vapor at 125°C. What is true...
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) -- 3 CO2(g) + 4H2O(g) Arxn = -2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3H8 a. -104.7 kJ/mol ob. +1407.7 kJ/mol C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol
16. + -/2 points was OSGenChem1 5.3.WA.033.0/10 Submissions Used The combustion reaction of propane is as follows. CHg(9) + 5 02(9) ► 3 CO2(g) + 4 H2O(1) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(9) + CO2(g) | AH = -393.5 kJ/mol reaction (2): H2(9) + 1/2 02(g) → H200 AH = -285.8 kJ/mol reaction (3): 3 C(s) + 4 H (9) CHg(9) AH = -103.8...
need help with
2. Use the following enthalpies of formation to calculate an approximate enthalpy of reaction, AHrxn for: (5 pts) C3H8 (g) + 502 (g) → 3CO2 (g) + 4 H20 (1) C(s) + O2 (g) - CO2 (g); AH = - 393.5 kJ/mol H2(g) + 42 02 (g) - H20 (1); AH = - 285.5 kJ/mol 3 C(s) + 4 H2(g) → C3H8 (g); AH r = - 103.8 kJ/mol
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values for reactions at 25°C, what is AH at 25°C for the following reaction: C3H3(g) + 502(g) + 4H2O(g) + 3CO2(g) AH = -2043 kJ 3C(s) + 4 H2(g) → C3H8 (g) 2H2(g) + O2(g) + 2H2O(g) AH° = -483.6 kJ
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