C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values...

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C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values for reactions at 25°C, what is AH at 25°C f

Answer 1

Answer #1

Multiply first equation with 3, (1) 3(18)+ 30219) - 360219) su= 3x(-393-5) kJ A4 = -1180-5 kJ Now, reverse second equation, (

Answer 2

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