Question

Name: CHM 111-01: General Chemistry I 10-pt. Takehome #7 Due Tuesday 10/29 by 5 PM. (1) (2 points ) Consider the reaction, Zn

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1. Zn(s) + 2HCl(aq) → ZnCl2 (aq) + H₂(g) DH = -152.4k] V=25.0mL M=2.OMHO. molauity = moles Vlina) moles=2.0x0.025 -0.05 moles

Add a comment
Know the answer?
Add Answer to:
Name: CHM 111-01: General Chemistry I 10-pt. Takehome #7 Due Tuesday 10/29 by 5 PM. (1)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (2) ( 2 points ) Compute AH for the reaction, 2 CH4 + C2H4(9) + 2...

    (2) ( 2 points ) Compute AH for the reaction, 2 CH4 + C2H4(9) + 2 H2(g) given the following data: H2(g) + } 02(g) + H20(1) AH° = -285.8 kJ CO2(g) + 2 H2O(l) + CH4(g) + 2 029) AH° = 890.3 kJ 2 C2H6(g) + 7 02(g) + 4CO2(g) + 6 H2O(1) AH° = -3120.8 kJ C2H4(9) + H2(g) → C2H6(9) AH° = -136.3 kJ

  • 1. Calculate AH for the reaction C2H4 (8) + H2() → C2H6), from the following data....

    1. Calculate AH for the reaction C2H4 (8) + H2() → C2H6), from the following data. C2H4 (g) + 3 02 (®) → 2 CO2 (s) + 2 H20 (1) C2H6 (g) + 7/2 02(g) → 2 CO2(g) + 3 H20 (1) H2 + 1/2O2() → H20 (1) AH = -1411. kJ/mole AH = -1560. kJ/mole AH = -285.8 kJ/mole 2. Calculate AH for the reaction 4 NH3(g) +502 (g) → 4 NO(g) + 6 H20 (g), from the following...

  • Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) +...

    Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...

  • 16. + -/2 points was OSGenChem1 5.3.WA.033.0/10 Submissions Used The combustion reaction of propane is as...

    16. + -/2 points was OSGenChem1 5.3.WA.033.0/10 Submissions Used The combustion reaction of propane is as follows. CHg(9) + 5 02(9) ► 3 CO2(g) + 4 H2O(1) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(9) + CO2(g) | AH = -393.5 kJ/mol reaction (2): H2(9) + 1/2 02(g) → H200 AH = -285.8 kJ/mol reaction (3): 3 C(s) + 4 H (9) CHg(9) AH = -103.8...

  • balance each of the following equations Fall 209 CHM 105.004 Exam 2 Answer all the question in order in the blue b...

    balance each of the following equations Fall 209 CHM 105.004 Exam 2 Answer all the question in order in the blue book. Plesse leave at least two lines between question and show your calculations for full credit. N-6.023 x 10” particles per mol: R 0.08.205 L-atm/(mol-K) b) Al2(PO4) 3 e) CuSO4-5 H2O 1. Calculate the molar masses of: a) (NH4)2SO4 2. Calculate: a) the number of atoms of calcium in a 10.50 g sample of the metal b) the mass...

  • Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) +...

    Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) + 6 F2 (g) → 2 CF4(g) + 4 HF (9) can be written as the sum of: CH4 (9) ► 2 C(s) + 2 Ha(o) AH = -52.3 kJ/mol 2 C(s) + 4 Faq) → 2 CF4g) SH -1380 kJ/mol 2 Haq) + 2 Fala) > 4 HF HE.1074 kJimol CsHe(g) + 6 F2 (g) → 2 CF.(g) + 4 HF (g) AH =...

  • Answe all please! Consider the following reaction carried out under constant pressure 2HCl(aq) + Zn(s) -...

    Answe all please! Consider the following reaction carried out under constant pressure 2HCl(aq) + Zn(s) - H2(g) + ZnCl2(s) AHpx = -80.97 kJ Calculate the heat associated with the complete reaction of 24.3 g of HCl with 16.8 g of Zn. 0-54.0 kJ 0-10.8 kJ O-55.2 kJ -20.8 kJ O-27.0 kJ Determine AHrxn for the reaction CO2(g) + 2 H2O(9) CH4(9) + 2 O2(g) given the following average bond energies (values given parentheses) C-H (414 kJ/mol) O=O (498 kJ/mol) C=0...

  • 6C02(g) + 6H2O(1)— C6H1206+602(g) Using standard thermodynamic data at 298K, calculate the free energy change when...

    6C02(g) + 6H2O(1)— C6H1206+602(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.92 moles of CO2(g) react at standard conditions. AGºrxn = Carbon AH°F (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 5.7 2.4 C(s, graphite) C(s, diamond) C(9) CC14 (1) 1.9 716.7 2.9 671.3 158.1 -135.4 -65.2 216.4 CCl4(9) -102.9 -60.6 309.9 CHCl3(1) -134.5 -73.7 201.7 CHCl3(9) -103.1 -70.3 295.7 CH4(9) -74.8 -50.7 186.3 CH3OH(g) -200.7 -162.0 239.8 CH3OH(1) -238.7 -166.3 126.8 H2CO(g) -116.0 219.0 HCOOH(g) -363.0...

  • 1. Hydrochloric acid can dissolve solid magnesium according to the reaection below. What minimum magnesium in...

    1. Hydrochloric acid can dissolve solid magnesium according to the reaection below. What minimum magnesium in grams can be dissolved by 8.52 g of HCI? (3 pts) Mg(s) + 2 HCl(aq) + MgCl2(aq) + H2(g) 2. Consider the reaction between NiS2 and O2 below. If 24.3 g of NiS2 reacts with 22.6 g of O2, what is the limiting reactant and theoretical yield of NiO? (5 pts) 2 NiSz(s) + 5 O2(g) 2 NiO(s) + 4 SO2(g) 3. The equation...

  • 1. What mass of natural gas (CH4) must you burn to emit 260 kJ of heat?...

    1. What mass of natural gas (CH4) must you burn to emit 260 kJ of heat? CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔH∘rxn=−802.3kJ 2.Consider the following thermochemical equation for the combustion of acetone, C3H6OC3H6O, the main ingredient in nail polish remover: C3H6O(l)+4O2(g)→3CO2(g)+3H2O(g)ΔH∘rxn=−1790kJ If a bottle of nail polish remover contains 173 mL of acetone, how much heat would be released by its complete combustion? The density of acetone is 0.788 g/mL 3.Zinc metal reacts with hydrochloric acid according to the following balanced equation: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) When...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT