Question

6C02(g) + 6H2O(1)— C6H1206+602(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.92 molesCarbon AH°F (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 5.7 2.4 C(s, graphite) C(s, diamond) C(9) CC14 (1) 1.9 716.7 2.9 671.3 158.1Hydrogen AH°F (kJ/mol) AG°f (kJ/mol) sº (J/mol K) H2(g) 130.7 H(g) 218.0 203.2 114.7 1536.2 H*(9) H+ (aq) 0 OH(aq) -230.0 -15

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6 co, Cs) + 6, o (4) - 41 204 +6 o Cs) 46 - 46, с. 4, 96 ) - [6ка (св.) +6 кад сноо)] я — 311 — [ext-334.4) + Gк (- 237.5) и

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