AHºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 0 0 130.7 Hydrogen H2 (g) H (g) H'...
6C02(g) + 6H2O(1)— C6H1206+602(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.92 moles of CO2(g) react at standard conditions. AGºrxn = Carbon AH°F (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 5.7 2.4 C(s, graphite) C(s, diamond) C(9) CC14 (1) 1.9 716.7 2.9 671.3 158.1 -135.4 -65.2 216.4 CCl4(9) -102.9 -60.6 309.9 CHCl3(1) -134.5 -73.7 201.7 CHCl3(9) -103.1 -70.3 295.7 CH4(9) -74.8 -50.7 186.3 CH3OH(g) -200.7 -162.0 239.8 CH3OH(1) -238.7 -166.3 126.8 H2CO(g) -116.0 219.0 HCOOH(g) -363.0...
Consider the reaction 2 CO2(g) +5 H2(e) C H2(e) + 4H2O(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: Submit Answer Retry Entire Group more group attempts remaining AH,(kJ/mol) AG® (kJ/mol) Sº (J/mol K) -238.7 -116.0 126.8 219.0 -363.0 249.0 135.1 -166.3 -110.0 -351.0 125.0 209.2 68.2 - 129.0 202.0 226.7 200.9 52.3 - 166.0 -53.0 -277.7 219.6 250.0 242.0 160.7 -13.0 -235.1 282.7 Carbon CH3OH (1) H2CO...
help with these please N2(g) + O2(g) 2NO(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: CH (9) +202(g) →CO2(g) + 2H2O(g) de manera en cas de este mai mare de mise en contact tenda Using standard thermodynamic data at 298K, calculate the free energy change when 1.62 moles of CH4(g) react at standard conditions. AGºrx Nz9) +202(g) +2NO2(g) Using standard thermodynamic data at 298K, calculate the free...
Nitrogen AHºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) N2 (g) 0 0 191.6 472.7 455.6 153.3 N(g) NH3 (g) -46.1 -16.5 192.5 NH3 (aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 NO (g) 90.3 86.6 210.8 NOCI (g) 51.7 66.1 261.8 NO2 (g) 33.2 51.3 240.1 N20 (g) 82.1 104.2 219.9 N204 (8) 9.2 97.9 304.3 Consider the reaction N2(9) + 202(9)—2NO2(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for this reaction at 298.15K...
Nitrogen Ahºf (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 191.6 N2(9) 0 0 N(g) 472.7 455.6 153.3 NH3(g) -46.1 -16.5 192.5 NH3(aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 90.3 86.6 210.8 NO(9) NOCI(g) 51.7 66.1 261.8 NO2(g) 33.2 51.3 240.1 N20(9) 82.1 104.2 219.9 N204(9) 9.2 97.9 304.3 N204(0) -20.0 97.0 209.0 N205(s) -42.0 134.0 178.0 N2H4(0) 50.6 149.3 121.2 N2H3CH3 () 54.0 180.0 166.0 HNO3(aq) -207.4 -111.3 146.4 HNO3(1) -174.1 -80.7 155.6 HNO3(9) -135.1 -74.7 266.4 NH4ClO4(s) -295.0...
Thermodynamic Quantities for Selected Substances at 298.15 K (25 °C) Substance AHºf (kJ/mol) AG°f (kJ/mol) S (J/K-mol) Oxygen O2 (g) H20 (1) 0 -285.83 205.0 69.91 -237.13 10 CHCOOH 0 Sulfur S (s, rhombie) 0 SO2(g) -269.9 SO3(g) -395.2 -300.4 31.88 248.5 256.2 OM-370.4 FASO for the decomposition of gaseous sulfur trioxide to solid elemental sulfur 3. The value of ASº for the d and gaseous oxygen, 2503 (g) → 28 (s, rhombie) + 302 (g) J/K. mol. (show your...
Use the data found in the Thermodynamic Values link under Reference Materials to calculate ΔHo (KJ), ΔSo (J/K) and ΔGo(KJ) and ΔGo from the equation ΔGo ≈ ΔHo - TΔSo at 25.0 oC for 1. 1 C2H5OH(g) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (g) (Do not change a coefficient that is shown) 2. 2 C4H10 (l) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (g) (Do not change a coefficient that is shown) 3. C2H5OH (l) → C2H4 (g) + H2O (g) ...
Use the data found in the Thermodynamic Values link under Reference Materials to calculate ΔHo (KJ), ΔSo (J/K) and ΔGo(KJ) and ΔGo from the equation ΔGo ≈ ΔHo - TΔSo at 25.0 oC for 1. C2H5OH (g) → C2H4 (g) + H2O (l) 2. 2 C4H10 (l) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (l) (Do not change a coefficient that is shown) 3. 2 C4H10 (g) + ___ O2 (g) → ___ CO2 (g) + ___ H2O (l) (Do not change a coefficient that...
help with this please Ca(OH)2(aq) + 2 HCl(aq) +CaCl2(8) + 2 H2O(1) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: N2(g) + O2(g) +2NO(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: 2CO(g) + O2(g) +2002(9) - der e en manos de 20, ali ne more than one so mi dicogna undan Using standard thermodynamic data...
2NH3(g) + 3O2(g) + 2CH4(g) 2HCN(g) + 6H2O(g)?H°f (kJ mol-1)S° (J K-1 mol-1)NH3(g)-46193O2(g)0205CH4(g)-75186HCN(g)135.1202H2O(g)-242189The above reaction is used in the industrial production of hydrogen cyanide. (The tabulated values ?H°fand S° are for 25°C. For the purposes of this question assume that ?H° and ?S° are invariant with temperature. This is not actually true but would generally be a reasonable approximation over "small" temperature ranges.)?H° is -939.8?S° is 165Calculate ?G° at 1005°C, for this equation.Are the following statements about this process True...