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Consider the reaction 2 CO2(g) +5 H2(e) C H2(e) + 4H2O(g) Using the standard thermodynamic data in the tables linked above, c
AH,(kJ/mol) AG® (kJ/mol) Sº (J/mol K) -238.7 -116.0 126.8 219.0 -363.0 249.0 135.1 -166.3 -110.0 -351.0 125.0 209.2 68.2 - 12
- 2.0 CuUH)2 (s) Cus (8) - 450.0 -49.0 -49.0 67.0 Fluorine F2 (g) F (g) AH° (kJ/mol) AGO (kJ/mol) Sº (J/mol K) 202.8 79.0 61.
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Answer #1

2002 Lg) + 5 h2 lg) - Catalg) +442018) ago for the deaction is- (C2H2) + 4 AGf (420)) - (2064 (202) + 5 AG (He). ago = ( 209\DeltaG0(reaction)= \DeltaG0f(product)-\Delta​​​​​​​G0f(reactant)

Using this you can find \Delta​​​​​​​G0 of the reaction and then by using \Delta​​​​​​​G0=RTlnKeq we can find Keq of the reaction.

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