If pentane, C5H12, reacts with excess oxygen according to CsH12 + O2 +5CO2+ H20 how many...

Question

Question

If pentane, C5H12, reacts with excess oxygen according to CsH12 + O2 +5CO2+ H20 how many grams of pentane are needed to produ

Answer 1

Answer #1

The balanced equation is

C₅H₁₂ + 8 O₂ ------> 5 CO₂ + 6 H₂O

6.023*10^23 molecules of pentane = 1 mole so

7.89 *10^23 molecules of pentane =

= 7.89 *10^23 molecules of pentane *(1 mole / 6.023*10^23 molecules of pentane)

= 1.31 mole of pentane

mass of 1 mole of pentane = 72.15 g so

the mass of 1.31 mole of pentane = 94.5 g

Therefore, the mass of pentane needed would be 94.5 g

Answer 2

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