If 2.72 mol of propane are reacted with excess oxygen according to C3H8 +502 3CO2 + 4H20 how many grams of H20 are p...

Question

Question

If 2.72 mol of propane are reacted with excess oxygen according to C3H8 +502 3CO2 + 4H20 how many grams of H20 are produced?

Answer 1

Answer #1

C3 Ho + 50 360g + 4H2O moles of propane - 2.72 mol. from stoichiomety 1 mol to gives 4 mol H₂O 2.72 mol to gives = 4x2.72 = 1

Answer 2

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