The combustion of propane may be described by the chemical equation C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g) How many grams of...

Question

Question

The combustion of propane may be described by the chemical equation

C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g)

How many grams of O2(g) are needed to completely burn 70.9 g C3H8(g)?

mass O2:

g O2

Answer 1

Answer #1

Molar mass of C3H8= 44 g/mol

molar mass of O2 = 32 g/mol

1 mol C3H8 react with 5 mol of O2

=> 44 g C3H8 react with = 532 g of O2

=> 1 g C3H8 react with =16044 g of O2 = 3.64 g of O2

=> 70.9 g C3H8 react with = 3.6470.9 g of O2= 257.82 g of O2

Answer 2

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