Question

If 8.58 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction?

C5H12 + 8O2 ----> 6H2O + 5CO2

Please explain how answer is found if possible.

Answer 1

From reaction

1mol of C₅H₁₂ produces 5 moles of CO₂

So, 8.58 mol of C₅H₁₂ produces 5*8.58 = 42.9 moles of CO₂

So, Total moles of CO₂ produced = 42.9 mol

or FRom reaction

8.58 mol C₅H₁₂ * ( 5 mol CO₂ / 1 mol C₅H₁₂) = 42.9 mol CO₂