Given a distribution of weight (162.9 lbs with standard deviation of 65.6 lbs), what sample size would be within 10 lbs of the population mean 90% of the time?
Use Matlab to find the sample size.
Standard Deviation , σ =
65.6
sampling error , E = 10
Confidence Level , CL= 90%
alpha = 1-CL = 10%
Z value = Zα/2 = 1.645 [excel
formula =normsinv(α/2)]
Sample Size,n = (Z * σ / E )² = ( 1.645
* 65.6 / 10 ) ²
= 116.429
So,Sample Size needed=
117
Given a distribution of weight (162.9 lbs with standard deviation of 65.6 lbs), what sample size...
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