Question


(8.12) In a sample of 1000 adults, 30% complain of suffering from insomnia. Use equation 8.10 to calculate the 95% confidence interval for this proportion and compare this interval to that found in table A.11.

(equation is P-(1.96*SE)<p<P+(1.96*SE)

95% Confidencel Sizes. In each cell, the top number represents the lower confidence limit and the bottom num represents the upper limit. Values from Rohlf and Sokal (2012) pA 11 ter als for pas Estimated by the SamplePr portion Pfo r Different Sample ber 20 0026 2442 0181 3199 0422 3722 0714 50 0119 1519 0403 2176 0711 2782 .1066 3385 .1462 100 0200 .1134 0534 1740 0890 2340 .1287 2893 .1741 200 500 0338 0727 1000 0379 0653 0.05 1494 .1060 2069 1495 2620 .1946 3147 2396 3672 0824 .1203 1289 1734 .1759 2259 2240 2779 2720 3294 3210 3804 1297 1208 1838 .1668 0.25 0.30 0.35 0.40 0.45 0.50 2898 2609 3419 4745 1396 5254 .1669 5764 2090 6277 2443 3996 2591 2281 3929 3576 4439 4060 4198 3322 4309 4190 5402 3177 5200 4299 4809 4690 5310 4560 6003 6411

Please answer and explain thank you!!!

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