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could you please answer this please on paper if possible been asked numerous times before but not best presented and not clear to understand thanks!!

2. A profit-maximising monopolist produces strawberry jam (J) and marmalade (M). These goods are produced according to a join
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Answer #1

(a)

Total profit is maximized when MR = MC for each product. Because Total Cost is a joint cost function, Marginal Cost (= dTC/dQ) is also a joint cost function. Hence price and quantity for each product depends on the quantity of the other product and hencem the goods are related in production.

For Jam,

Total revenue (TRJ) = pJ x qJ = 10qJ - qJ2

For Marmalade,

Total revenue (TRM) = pM x qM = 20qM - 2qM2

Overall revenue (TR) = TRJ + TRM = 10qJ - qJ2 + 20qM - 2qM2

Profit (Z) = TR - TC = 10qJ - qJ2 + 20qM - 2qM2 - (qJ + qM)2

Z = 10qJ - qJ2 + 20qM - 2qM2 - (qJ2 + qM2 + 2qJqM)

Z = 10qJ - qJ2 + 20qM - 2qM2 - qJ2 - qM2 - 2qJqM

Z = 10qJ - 2qJ2 + 20qM - 3qM2 - 2qJqM

Profit-maximizing conditions are:

php7TB5Uz.pngZ/phpRN1CLf.pngqJ = 0 (i) and

phpgwqaRD.pngZ/phpsVAJHg.pngqM = 0 (ii).

phpHD5XV0.pngZ/phpdhrGas.pngqJ = 10 - 4qJ - 2qM = 0

4qJ + 2qM = 10

2qJ + qM = 5............(1)

phpD0PnZx.pngZ/phpG9c8sn.pngqM = 20 - 6qM - 2qJ = 0

2qJ + 6qM = 20........(2)

(b)

Equilibrium is achieved by solving equations (1) and (2). Subtracting (1) from (2),

5qM = 15

qM = 3

qJ = (5 - qM)/2 [from (1)] = (5 - 2)/2 = 2/2 = 1

pM = 20 - (2 x 3) = 20 - 6 = 14

pJ = 10 - 1 = 9

(c)

A marginal unit tax on jam will increase the production cost for jam, so production of jam will fall. Hence, quantity of marmalade produced will increase.

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