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The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 256.5 and a standard deviation of 68.2. (All units are 1000 cells/HL.) Using the empirical rule, find each approximate percentage below. a. What is the approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 120.1 and 392.9? b. What is the approximate percentage of women with platelet counts between 51.9 and 461.1?The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 256.5 and a standard deviation of 68.2. ​(All units are 1000 ​cells/mu​L.) Using the empirical​ rule, find each approximate percentage below. a. What is the approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 120.1 and 392.9​? b. What is the approximate percentage of women with platelet counts between 51.9 and 461.1​?

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Answer Date: 21/01/2019 a) approximately percentage of women with platelet counts between 120.1 First, compute the z score then find probability based on standard normal table. For x = 120.1 converts to 120.1-256.5 68.2 2.00 For x 392.9 converts to 392.9-256.5 68.2 -2.00From the standard normal distribution table, the associated probability for z values and subtracts the probabilityis, p(120.1 sr 3 392.9)-p(-2.00 s z 3 2.00) - p(z s 2.00)- p(z s-2.00) 0.9772-0.0228 0.9544 95.44% The approximately percentage of women with platelet counts between 120.1 and 392.9 is 95.44% b) The approximate percentage of women with platelet counts between 51.9 and 461.1 is First, compute the z score then find probability based on standard normal table. Forx -51.9 converts to51.9 256.5 68.2 -3.00 For x 461.1 converts to 461.1-256.5 68.2 3.00 From the standard normal distribution table, the associated probability for z values and subtracts the probabilityis, p(51.9 sxs461.1) p(3.00 szs3.00) - p(z s 3.00) p(zs-3.00) -0.9987-0.0013 0.9974 99.74%The approximate percentage of women with platelet counts between 51.9 and 461.1 s 99.74%

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