Let CP represent the event that the ankle was truly fractured, and let T+ represent the...
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Let CP represent the event that the ankle was truly fractured, and let T+ represent the event that the test said it was. From the table, estimate P(CP|T+) (the positive predictive value and P(CA|T-) (the negative predictive value).
Predicted by the Ottawa Ankle Test Truth Regarding Fracture
Not Fractured | Fractured | Totals
Not Fractured | 51 | 5 | 56
Fractured | 277 | 88 | 365
Totals | 328 | 93 | 421
Homework Answers
P(CP|T+) =P(really fractured given tested positive for fracture)=5/93=0.053763
P(CA|T-)=P(not fractured given tested negative for fracture)=277/328=0.844512
Add Answer to:
Let CP represent the event that the ankle was truly fractured,
and let T+ represent the...
Questions TABLE 3.10 Ankle Test Results Let CP represent the event that the ankle was truly...
Questions TABLE 3.10 Ankle Test Results Let CP represent the event that the ankle was truly fractured, and let T+ represent the event that the test said it was. From the table, estimate the positive predictive value and the negative predictive value. 1. Truth Regarding Fracture Predicted by the Ottawa Ankle Test Not Totals Fractured Not Fractured 51 56 Fractured 277 365 Totals 328 93 421 2. Which do you think a patient would be more interested in, P(T+|CP) or...
Questions 3 please Questions TABLE 3.10 Ankle Test Results 1. Let CP represent the event that...
Questions 3 please
Questions TABLE 3.10 Ankle Test Results 1. Let CP represent the event that the ankle was truly fractured, and let T+ represent the event that the test said it was. From the table, estimate the positive predictive value and the negative predictive value. Truth Regarding Fracture Predicted by the Ottawa Ankle Test Not Fractured Totals 56 Not Fractured 51 365 Fractured 277 328 93 421 Totals 2. Which do you think a patient would be more interested...
BEYOND THE NUMBERS 3.10 | LEARNING OUTCOMES 1 TO 3 BEYOND THE NUMBERS 3.10 LEARNING OUTCOMES...
BEYOND THE NUMBERS 3.10 | LEARNING OUTCOMES 1 TO 3
BEYOND THE NUMBERS 3.10 LEARNING OUTCOMES 1 TO 3 Bayes' Rule EXTEND Name Section Number To be graded, all assignments must be completed and submitted on the original book page Background The notation P(A|B) is read as "the probability of A, given B, has occurred." So the "I" symbol is read as "given." Formally, A and B are called events and P(AIB) is a conditional probability Bayes rule is a...
Background The notation P(AlB) is read as "the probability of A, given B, has occurred." So...
Background The notation P(AlB) is read as "the probability of A,
given B, has occurred." So the "" symbol is read as "given."
Formally, A and B are called events and P(AB) is a conditional
probability Bayes' rule is a very useful way of relating
conditional and unconditional probabilities. According to this
rule, for any two events A and B, we have: P(B) Let's use "T+" to
denote the event "the screening test concludes that the condition
(disease, pregnancy, etc,)...
3. Let C be the event that a patient suffers from a certain condition, and let T denote a positive result from a lab te...
3. Let C be the event that a patient suffers from a certain condition, and let T denote a positive result from a lab test that is designed to detect the presence of said condi- tion. Suppose that the proportion of the population that actually has the condition IS E E (0,1). Additionally, suppose that, when the condition is actually present in a patient, the test is positive with probability a (0,1). On the other hand, when the patient does...
Questions TABLE 3.10 Ankle Test Results Let CP represent the event that the ankle was truly fractured, and let T+ represent the event that the test said it was. From the table, estimate the positive predictive value and the negative predictive value. 1. Truth Regarding Fracture Predicted by the Ottawa Ankle Test Not Totals Fractured Not Fractured 51 56 Fractured 277 365 Totals 328 93 421 2. Which do you think a patient would be more interested in, P(T+|CP) or...
Questions 3 please
Questions TABLE 3.10 Ankle Test Results 1. Let CP represent the event that the ankle was truly fractured, and let T+ represent the event that the test said it was. From the table, estimate the positive predictive value and the negative predictive value. Truth Regarding Fracture Predicted by the Ottawa Ankle Test Not Fractured Totals 56 Not Fractured 51 365 Fractured 277 328 93 421 Totals 2. Which do you think a patient would be more interested...
BEYOND THE NUMBERS 3.10 | LEARNING OUTCOMES 1 TO 3
BEYOND THE NUMBERS 3.10 LEARNING OUTCOMES 1 TO 3 Bayes' Rule EXTEND Name Section Number To be graded, all assignments must be completed and submitted on the original book page Background The notation P(A|B) is read as "the probability of A, given B, has occurred." So the "I" symbol is read as "given." Formally, A and B are called events and P(AIB) is a conditional probability Bayes rule is a...
Background The notation P(AlB) is read as "the probability of A,
given B, has occurred." So the "" symbol is read as "given."
Formally, A and B are called events and P(AB) is a conditional
probability Bayes' rule is a very useful way of relating
conditional and unconditional probabilities. According to this
rule, for any two events A and B, we have: P(B) Let's use "T+" to
denote the event "the screening test concludes that the condition
(disease, pregnancy, etc,)...
3. Let C be the event that a patient suffers from a certain condition, and let T denote a positive result from a lab test that is designed to detect the presence of said condi- tion. Suppose that the proportion of the population that actually has the condition IS E E (0,1). Additionally, suppose that, when the condition is actually present in a patient, the test is positive with probability a (0,1). On the other hand, when the patient does...
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