Let X be the mass of Grade A Gala Apple,
Thus, X ~
Let Y be the sum of a sample of n Grade A Gala Apple then,
Y = ( As per Reproductive property of the normal distribution)
So, P(Y >= 2000) < 0.04
Z = (Y-n*)/()
For p = 0.04 on std. normal curve
Z = 1.75
To satisfy the above condition,
Z <= 1.75
(Y-n*)/() <= 1.75
Soving the above equation,
n < 9.62
That is the maximum number of these Gala apples that should be placed into one M1A1 package is 9.
For n = 9,
z = (2000-205*9)/ * 5
z = 10.33
Probability of P(Z>=10.33) < .00001
while for n = 10
z = (2000-205*10)/ *5
z = -3.16
Probability of P(Z>=-3.16) = 0.9992
Hence, the maximum number of these Gala apples that should be placed into one M1A1 package so that the mass limit is exceeded less than 4% of the time is 9.
The mass of a Grade A Gala apple is Normally distributed with mean 205 grams and...
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