Question 7 The mean time taken by all participants to run a road race was found...

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Answer 1

Answer #1

By Chebyshev's inequality, we know

$Prleft ( |X-mu|leq ksigma ight )=1-{1over k^2}$

Since 120-150-3 × 10 and 180-150 3 × 10 ,

So

Pr( 120 < X < 180) Pr (X-150| < 2 × 10) 32 0,888

Hence the required probability is 88.89%

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Answer 2

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