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Suppose you sample one value from a uniform distribution with a = 0 and b= 50. a. What is the probability that the value will

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Answer #1

a)
Here, the given values of lower limit, a = 0 and upper limit, b = 50

For Uniform Distribution,
P(x1 <= X <= x2) = (x2 - x1)/(b - a)
P(35 <= X <= 45) = (45 - 35)/(50 - 0)
P(35 <= X <= 45) = 0.2


b)

Here, the given values of lower limit, a = 0 and upper limit, b = 50

For Uniform Distribution,
P(x1 <= X <= x2) = (x2 - x1)/(b - a)
P(6 <= X <= 23) = (23 - 6)/(50 - 0)
P(6 <= X <= 23) = 0.34


c)

Mean = (a + b)/2
Mean = (0 + 50)/2 = 25


d)

Standard Deviation = sqrt((b - a)^2/12)
Standard Deviation = sqrt((50 - 0)^2/12 = 14.4338

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