solution:
Lets perform the above experiment 10000 times times using a python code.
lets understand the program
noOfTrial = 10000 which means we conduct the experiment 10000 times.
noOfToss = 5 which means each time we flip the coin 5 times
in each flip the program either generates a 0 or 1 randomly using randint(0,1)
we onsider a 0= tail and 1 = head
now we want exactly 3 heads and remaining 2 will be tail
so sum of result should be exactly 3
for eg 01011 or 11001 are favorable outcomes and divided by noOfTrials (10000) to find out the probability
lets run the monte carlo simulation program
the probability turns out to be 0.3087
please give me thumb up
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