Question

A galvanic cell is powered by the following redox reaction: 

5 Cl₂(g)+I₂(s)+6 H₂ O(I) → 10 Cl^-(aq)+2 IO₃^-(a q)+12 H⁺(a q)

Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab.

• Write a balanced equation for the half-reaction that takes place at the cathode.

•  Write a balanced equation for the half-reaction that takes place at the anode. 

• Calculate the cell voltage under standard conditions.

Answer 1

1) At Cathode, reduction takes place. Thus, balanced reaction is :

5Cl₂(g) + 10e^- -> 10Cl^-(aq)

2) At anode oxidation takes place. Thus, balanced reaction is :

I ₂(g) - 6H₂O(l) -> 2IO₃^-(aq) + 12H⁺(aq) + 10e^-

3) E°cell = E°cathode - E° anode

= 1.36 - 1.20

= 0.16 V