Solution:
Given: The cost of repairs for each of the four crashes : $416 , $459 , $417 , $216
Part a)
Range=L - S
Where L = Largest observation = 459 and S = Smallest Observation = 216
thus
Range = $459 - $216
Range = $ 243
Part b)
Sample variance:
thus we need to make following table:
x | x^2 |
416 | 173056 |
459 | 210681 |
417 | 173889 |
216 | 46656 |
Thus
Part c)
Sample standard Deviation : s
An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $417, $464, $407, $218 Compute the range, sample variance, and sample standard deviation cost of repair.
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in java no mathcall please ennas are out of date.Please sign was wkollieemail.cpeedu so we can verily your subscription Sign In ASSIGNMENT Unit 9 Methods, Arrays, and the Java Standard Class Library Reimplementing the Arrays class (60 points) The Arrays class, which is also part of the Java standard class library, provides various class methods that perform common tasks on arrays, such as searching and sorting. Write a public class called MyArrays, which provides some of the functionality which is...