An insurance company crashed four cars in succession at 5 miles per hour. The cost of...

Question

Question

An insurance company crashed four cars in succession at 5 miles per hour. The cost of...

An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $417, $464, $407, $218

Compute the range, sample variance, and sample standard deviation cost of repair.

math Statistics-And-Probability

Add a comment Improve this question Transcribed image text

Answer 1

✔ Recommended Answer

Answer #1

Given sample of data in ascending Order 218, 407, 417, 464 Range = maximum-Minimum E 464 - 218 - 12467 Sample mean (a) = Eau = 417+ 464 + 407 + 218 4 = 1906 - 376.5 sample variance in 112,- Sia-v 11 417–376.57 +(454 – 376.99 +..

Dear student , please like it.

Thanks.

Add a comment

Answer 2

Similar Homework Help Questions

An insurance company crashed four cars in succession at 5 miles per hour. The cost of...

An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $420, $465, $407, $222 . Compute the range, sample variance, and sample standard deviation cost of repair. Compute the mean, median, and mode cost of repair. Compute the mean, median, and mode cost of repair. The mean cost of repair is $__ The median cost of repair is $__ The mode cost of repair is $__...
An insurance company crashed four cars in succession at 5 miles per hour. The cost of...

An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $420, $459, $412, $225 . Compute the range and sample standard deviation cost of repair.
An insurance company crashed four cars of the same model at 5 miles per hour. The...

An insurance company crashed four cars of the same model at 5 miles per hour. The costs of repair for each of the four crashes were $ 409, $428, $457, and $237 . Compute the mean, median, and mode cost of repair

An insurance company crashed four cars of the same model at 5 miles per hour. The...

An insurance company crashed four cars of the same model at 5 miles per hour. The costs of repair for each of the four crashes were $435,$448,$467, and $229. Compute the mean,median, and mode cost of repair.
sals are out of date. Please sign in as re e du so we can verify...

sals are out of date. Please sign in as re e du so we can verify your subscription An insurance company crashed four cars in succession at 5 miles per hour The cost of repair for each of the four crashes was $416, $459, $417, $216 Compute the range, sample variance, and sample standard deviation cost of repair. The range is $ sample variance and sample standard deviation cost of repair
cars of the same model at 5 miles per hour. The oosts of repair for each...

cars of the same model at 5 miles per hour. The oosts of repair for each of the four crashes wore $419, s438, $486, and $240 .Compute the D A. The mean cost of repair is s(Round to the nearest cent as needed.) the median cost of repair. Select the corect choloe below and, il necessary, filt in the answer box to OA. Tho median oost of roper is SⅢ (Round to the nearest cert as 8. The median does...

In crash tests at 5 miles per hour of 23 randomly selected midsize cars, the mean...

In crash tests at 5 miles per hour of 23 randomly selected midsize cars, the mean bumper repair cost is $741 with a standard deviation of $205. In similar tests of 14 randomly selected small cars the mean bumper repair cost is $473 with a standarc deviation of $190. Assume the populations of repair costs for small and midsize cars are approximately normally distributed. 1. Estimate the difference between mean repair costs for midsize and small cars using 90% level...
An insurance institute routinely conducts crash tests on vehicles to determine the cost of repairs. The...

An insurance institute routinely conducts crash tests on vehicles to determine the cost of repairs. The following data represent the vehicle repair costs for mini-and micro-car models from a recent year resulting from frontfull and rear full crash tests at 5 miles per hour. Treat these data as a simple random sample of 14 low.impact crashes. It has already been verified that the data are normally distributed and that s 1103.084 dollars. Construct and interpreta 95% confidence interval for the...
4. (12 pts) The speed limit on a highway is 70 miles per hour. A sample...

4. (12 pts) The speed limit on a highway is 70 miles per hour. A sample of 8 cars are clocked at 69 mph, with a sample standard deviation of 5 miles per hour. Can we say, with at least 90 percent confidence that the average speed on the road is above 65? tcale = tarit Can we be at least 90 percent confidence that the average speed >70?

The accompanying data represent the miles per gallon of a random sample of cars with a three-cylinder, 1.0 liter engine.

The accompanying data represent the miles per gallon of a random sample of cars with a three-cylinder, 1.0 liter engine.(a) Compute the z-score corresponding to the individual who obtained 43.4 miles per gallon. Interpret this result.(b) Determine the quartiles.(c) Compute and interpret the interquartile range, IQR.(d) Determine the lower and upper fences. Are there any outliers?(a) Compute the z-score corresponding to the individual who obtained 43.4 miles per gallon. Interpret this result.The z-score corresponding to the individual is _______ and...

An insurance company crashed four cars in succession at 5 miles per hour. The cost of...

Homework Answers

Add Answer to:
An insurance company crashed four cars in succession at 5 miles per hour. The cost of...

Post as a guest

Earn Coins