Solution:
The test statistics,
t0 = ( - )/ (s/)
= (519 - 512 ) / ( 117 / 1800 )
= 2.54
The test statistic is 2.54
motoccom/Rudent/Perlomeworkahomeworld-5377 question d e alsedd:561/24 online Venise Davis & 11/10/19 5:47 PM Save 2198 MATH 241-92...
Amath teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam Based on data from the administrator of the exam, scores are normally distributed with u 512. The teacher obtains a random sample of 1800 students, puts them through the review class, and finds that the mean math score of the 1800 students is 519 with a standard deviation of 117. Complete parts (a) through (d)...
y of IU 1 cup Score: 0.22 of 1 pt Question Help 10.3.31-T Amath teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the administrator of the exam, scores are normally distributed with 512. The teacher obtains a random sample of 1800 students, puts them through the review class, and finds that the mean math score of the 1800 students is...
A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the administrator of the exam, scores are normally distributed with mu equalsμ=519519. The teacher obtains a random sample of 20002000 students, puts them through the review class, and finds that the mean math score of the 20002000 students is 525525 with a standard deviation of 114114. Complete parts (a) through...
A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the administrator of the exam, scores are normally distributed with mu equals510. The teacher obtains a random sample of 1800 students, puts them through the review class, and finds that the mean math score of the 1800 students is 515 with a standard deviation of 111. Complete parts (a) through...