Question

Amath teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam Based on data from the administrator of the exam, scores are normally distributed with u 512. The teacher obtains a random sample of 1800 students, puts them through the review class, and finds that the mean math score of the 1800 students is 519 with a standard deviation of 117. Complete parts (a) through (d) below. Find the P-value. The P-value is (Round to three decimal places as needed.) onswer hay and then click Check Answer

Answer 1

Solution :

This is the two tailed test .

The null and alternative hypothesis is ,

H₀ :  $\mu$ = 512

H_a : $\mu$ > 512

Test statistic = z

= ($\bar x$ - $\mu$) / $\sigma$ / $\sqrt$n

= (519 - 512) / 117 / $\sqrt$1800

Test statistic = 2.538

P(z > 2.538) = 1 - P(z < 2.538) = 1 - 0.994

P-value = 0.006