(a) Multiple linear regression:
Regression Analysis | |||||||
R² | 0.979 | ||||||
Adjusted R² | 0.972 | n | 10 | ||||
R | 0.989 | k | 2 | ||||
Std. Error | 2.497 | Dep. Var. | P | ||||
ANOVA table | |||||||
Source | SS | df | MS | F | p-value | ||
Regression | 1,988.4641 | 2 | 994.2321 | 159.49 | 1.45E-06 | ||
Residual | 43.6359 | 7 | 6.2337 | ||||
Total | 2,032.1000 | 9 | |||||
Regression output | confidence interval | ||||||
variables | coefficients | std. error | t (df=7) | p-value | 95% lower | 95% upper | std. coeff. |
Intercept | 118.3723 | 0.000 | |||||
Z | 0.0812 | 0.0267 | 3.042 | .0188 | 0.0181 | 0.1443 | 0.242 |
p | -7.5795 | 0.7535 | -10.059 | 2.06E-05 | -9.3613 | -5.7978 | -0.801 |
Predicted values for: P | |||||||
95% Confidence Interval | 95% Prediction Interval | ||||||
Z | p | Predicted | lower | upper | lower | upper | Leverage |
180 | 3.5 | 106.460 | 99.644 | 113.276 | 97.443 | 115.477 | 1.333 |
A linear model seems appropriate
(b) b0 = 118.3723, b1 = 0.0812, p = -7.5795
The regression equation is P = 118.3723 + 0.0812 Z - 7.5795p
(c) Predicted P = 106.46
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