Question

12. Let the number of Chocolate chips in a oatmeal cookie have a Poisson distribution. We want the probability that a cookie of this type contains at least three chocolate chips to be greater than 0.98. Find the smallest value of the mean that the distribution can take. (You may need a graphing calculator)

Answer 1

type chocolate weater than 0.94 Given, The probability that a cookie of this contains areast three [cookies chips i.e. P(X73) chocolate chips it. PlX713) $0.98 1 - P( x < 3) < 0.88 - Plus) < 0.98-1 + pln<3) e poor i plll<) < 0.02 >) p(x = 0) + P(x =1) + p(x=2) < 0.02 < 0.02 21 01 e A(0) + et (0) telan) <0.02 Take "e" as common factor, -) en (! +^+ < 0.02 -) en ( x + 24 +2) <0.02 [rake wangu as ziemy 2) et ( 8°42142) < 0.02 X2

- e*(1+2x+2) < 0.04 (x+ 2x+2) a 0.04. et (OY) I etř tetrtet 20:02 By equating the above equation we get Y 75166. 1. The smallest value that "x" can is - 7.51661 take